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3 years ago

10

What is the relationship between the variance and standard deviation? variance is the positive square root of the standard devia

tion?

1 answer:

lana [24]3 years ago

6 0

Variance of a continuous random variable X is defined as

$\int\limits_D {(x-\mu)^2f(x)} \, dx$

Standard deviation is defined as

$\sigma = \sqrt{Var(X)}$

Hence standard deviation is the positive square root of variance.

You might be interested in

• What can you say about the values of 180 and 2x2x3x3x5?

kiruha [24]

Answer:

2×2×3×3×5 are the prime factors of 180

Step-by-step explanation:

If you draw a factor tree, you would find that 2x2x3x3x5 are the prime factors of 180

hope this helps :)

8 0

3 years ago

12 (x+1/6) = 8 20 points

Aliun [14]

Answer:

12x + 2

Step-by-step explanation:

12 is multiplyed by both the x and the (1/6) since it is outside the equation.

so 12 times x = 12x since we dont know what x is

and 12 times (1/6) = (12/6) = 2

7 0

3 years ago

Find the probability of at least three successes in six trials of a binomial experiment in which the probability of success is 5

Amanda [17]

Answer:

31.3%

Step-by-step explanation:

Start by doing the binomial expansion of (x+y)^6 where x represents success. This is

(x^6y^0) + 6(x^5y^1) +15(x^4y^2) +20(x^3y^3) +15(x^2y^4) +6(x^1y^5) +(x^0y^6)

We are interested in the x^3y^3 term which represents exactly 3 successes. Since the probability of success and failure are both .5 we should be able to figure this out just using the coefficients of the terms which is

20/64 = .3125 which is 31.25% Rounding yo the nearest tenth gives us

8 0

3 years ago

An open-top box with a square base is to have a volume of 4 cubic feet. Find the dimensions of the box (in ft) that can be made

Lemur [1.5K]

Answer:

The dimension of box= $2ft\times 2ft\times 1ft$

Step-by-step explanation:

We are given that

Volume of box=4 cubic feet

Let x be the side of square base and h be the height of box

Volume of box= $lbh=x^2h$

$4=x^2h$

$h=\frac{4}{x^2}$

Now, surface area of box,A= $x^2+4xh$

$A=x^2+4x(\frac{4}{x^2})=x^2+\frac{16}{x}$

$\frac{dA}{dx}=2x-\frac{16}{x^2}$

$\frac{dA}{dx}=0$

$2x-\frac{16}{x^2}=0$

$2x=\frac{16}{x^2}$

$x^3=8$

$x=2$

$\frac{d^2A}{dx^2}=2+\frac{32}{x^3}$

Substitute x=2

$\frac{d^2A}{dx^2}=2+\frac{32}{2^3}=2+4=6>0$

Hence, the area of box is minimum at x=2

Therefore, side of square base,x=2 ft

Height of box,h= $\frac{4}{2^2}=1 ft$

Hence, the dimension of box= $2ft\times 2ft\times 1ft$

5 0

3 years ago

Please help me I’m working on a math test and I’m struggling with this problem: The Aon center in Chicago is one of the worlds t

Nina [5.8K]

Answer:

They are 14.2 feet high each

Step-by-step explanation:

1136/80=14.2

4 0

3 years ago

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