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slega [8]
2 years ago
11

Please help and explain 20points

Mathematics
1 answer:
m_a_m_a [10]2 years ago
7 0

Hey, there, Brooklyn! For the first problem, set up a proportion. Think of the line that separates the numerator and denominator is the word 'per'. If it's 0.75 yd per costume, then your fraction is \frac{0.75(yards)}{1(costume)}. If she buys 6 yards, simply multiply 6 * 0.75, which is 4.5. However, making 4.5 costumes doesn't sound too possible, does it? It's better to just say she can make 4 costumes.

Now let's look at the second problem. If just one side has a length of (4x - 2y), then that means there must be another side with the same length, as it is a rectangle we're talking about here. That means we should multiply the known length by two and subtract it from the perimeter like this:

12x + 8y - 2(4x - 2y)

Remember the PEMDAS method. Distribute the 2;

12x + 8y - 8x + 4y

Now combine like terms: 12x - 8x + 8y + 4y

--> 6x + 12y

Now we have an answer, but it's not the right one. You see, this is the length of both of the unknown lengths. To get the right answer, divide this by 2. The other side is 3x + 6y units long. Hope this helped.

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Which polygon has an interior angle sum of 1080
Crank
Octagon has 8 sides so the sum of the angles of the octagon is 180(8-2)=180 (6)=1080 degrees
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3 years ago
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An insurance company examines its pool of auto insurance customers and gathers the following information: (i) All customers insu
ankoles [38]

The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

An insurance company examines its pool of auto insurance customers and gathers the following information: (i) All customers insure at least one car. (ii) 70% of the customers insure more than one car. (iii) 20% of the customers insure a sports car. (iv) Of those customers who insure more than one car, 15% insure a sports car. Calculate the probability that a randomly selected customer insures exactly one car, and that car is not a sports car?

Answer:

P( X' ∩ Y' ) = 0.205

Step-by-step explanation:

Let X is the event that the customer insures more than one car.

Let X' is the event that the customer insures exactly one car.

Let Y is the event that customer insures a sport car.

Let Y' is the event that customer insures not a sport car.

From the given information we have

70% of customers insure more than one car.

P(X) = 0.70

20% of customers insure a sports car.

P(Y) = 0.20

Of those customers who insure more than one car, 15% insure a sports car.

P(Y | X) = 0.15

We want to find out the probability that a randomly selected customer insures exactly one car, and that car is not a sports car.

P( X' ∩ Y' ) = ?

Which can be found by

P( X' ∩ Y' ) = 1 - P( X ∪ Y )

From the rules of probability we know that,

P( X ∪ Y ) = P(X) + P(Y) - P( X ∩ Y )    (Additive Law)

First, we have to find out P( X ∩ Y )

From the rules of probability we know that,

P( X ∩ Y ) = P(Y | X) × P(X)       (Multiplicative law)

P( X ∩ Y ) = 0.15 × 0.70

P( X ∩ Y ) = 0.105

So,

P( X ∪ Y ) = P(X) + P(Y) - P( X ∩ Y )

P( X ∪ Y ) = 0.70 + 0.20 - 0.105

P( X ∪ Y ) = 0.795

Finally,

P( X' ∩ Y' ) = 1 - P( X ∪ Y )

P( X' ∩ Y' ) = 1 - 0.795

P( X' ∩ Y' ) = 0.205

Therefore, there is 0.205 probability that a randomly selected customer insures exactly one car, and that car is not a sports car.

6 0
3 years ago
Train A leaves New York for California at the same time Train B leaves California for New York. They are 2900 miles apart. They
professor190 [17]

Answer:

(A) 120 mph

(B) -120 mph

(C) 12 hours 5 minutes.

Step-by-step explanation:

Given that,

New York and California are 2900 miles apart,

Both the trains A as well as B travel at an average speed of 120 mph.

Assuming that the path between the starting point in New York and the ending point in California is straight, so the given distance of 2900 miles is actually the shortest distance which is the displacement between the source and destination.

So, the given speed on the straight path is actually the velocity.

Assuming that the velocity is positive in the direction from New York towards California.

(A) So, the velocity of train A (towards California)  = 120 mph.

(B) The velocity of train B (towards New York) = -120 mph.

(C) Bothy are moving towards each other, so the relative velocity between them is 120+120=240 mph, and the initial distance between them is 2900 miles.

When they meet, the displacement between them becomes zero, displacement covered= 2900-0=2900 miles.

So, the time, t, taken to cover the displacement 2900 miles with a relative velocity of 240 mph is

t=\frac{2900}{240} [as time= displacement / relative velocity]

\Rightarrow t=12\frac{1}{12} hours

=12 hours 5 minutes.

7 0
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Suppose you know that ∠S and ∠Y are complementary, and that m∠S = 2(m∠Y) − 60°. Find m∠Y.
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Answer:

m∠Y=50°

Step-by-step explanation:

So, we know that ∠S+∠Y=90 and that m∠S=2(m∠Y)-60.

If you plug those things into the equation, you get (2[m∠Y]-60)+m∠Y=90.

Then you multiply 2 and m∠Y: 2m∠Y-60+m∠Y=90.

Combine like terms: 3m∠Y-60=90.

Then you add 60 to both sides: 3m∠Y=150

Divide 3 on both sides: 3∠Y=50

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Answer:

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Step-by-step explanation:

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