Answer:
if full_admission_price = f and discount_amount = d
=> Price of a discount admission = d/f
total_weight
quantity
weight of one item = total_weight/quantity
for i in range(80, 18, -2):
print(i, end=' ')
Explanation:
The first two questions are just mathematical to get a single quantity given some relationship. So, its basically division
For the python code, I used the python's range function which takes in three arguments. The first one is the starting value, the second one is the terminating value which is the number before the terminating value and the last one specifies the common difference popularly known as step in the language. Since the step is 2, only even numbers are printed out. In the print function, I made use of the end keyword specifying a space (' ') as the end. This ensures that the print is done in the same line with a space seperating them. Without that specification, each result will printed in a newline
Aaaaaaaeeeeeeeeiiiiiioooooouuuuuu
Answer:
access the computer remotely
Explanation:
The best option would be to access the computer remotely. This allows you to remotely view the computer and control it from anywhere in the world. This allows you to take full control, analyze, and fix the problem that the individual is having without having to explain step by step to the user what they have to do. This can be accomplished through a direct IP connection or through a third-party software, which the user will need to have installed on their computer.
Answer:
Following code will store the largest value in array parkingTickets in the variable mostTickets
mostTickets = parkingTickets[0];
for(int k = 0; k<parkingTickets.length; k++)
{
if(parkingTickets[i]>mostTickets)
{
mostTickets = parkingTickets[i];
}
}
Explanation:
In the above code segment, initially the number of tickets at first index is assumed as largest value of tickets in array.
Then using a for loop each value in the array parkingTickets is compared with the current mostTickets value.
If the compared value in parkingTickets array is larger than the current mostTickets value. Then that value is assigned to mostTickets.
This process is repeated for all elements in array.
Thus after looping through each element of array the largest value in array will get stored in mostTickets variable.
