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Blizzard [7]
3 years ago
11

What is the answer?

Mathematics
1 answer:
lukranit [14]3 years ago
8 0
A) 4/9 = g/36
b) g = 16
c) 52 total pints, 8pints in a gallon, so 6.5 gallons
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Please please please help me
alexira [117]

A and can I be brainliest? :3

7 0
3 years ago
What can I multiply 4/3 by to make it 1⅓​, jk what's up
Simora [160]

1.<u>3 </u>x 1= 1.<u>3 </u>hope this helped

7 0
3 years ago
Explain how to find the inequality that represents the graph.
Aloiza [94]

The inequality that represents the given graph is y < x/5 -2 OR 5y < x - 10

<h3>Graph of Inequality</h3>

From the question, we are to determine the inequality that represents the graph

First, we will assume the inequality is a straight line and we will determine the equation of the line

From the graph, we have two points on the line

(0, -2) and (5, -1)

Using the formula for the equation of a line with two given point

(y - y₁)/(x -x₁) = (y₂ - y₁)/ (x₂ - x₁)

x₁ = 0

y₁ = -2

x₂ = 5

y₂ = -1

Thus,

(y - -2)/(x - 0) = (-1 - -2)/ (5 - 0)

(y +2)/(x - 0) = (-1 + 2)/ (5 - 0)

(y +2)/(x ) = 1/ 5

5(y + 2) =1(x)

5y + 10 = x

5y = x - 10

y = 1/5(x) - 2

y = x/5 - 2

Now,

Since the solution is below the line and the line is dotted

The inequality becomes

y < x/5 -2

OR

5y < x - 10

Hence, the inequality that represents the given graph is y < x/5 -2 OR 5y < x - 10

Learn more on Graph of Inequality here: brainly.com/question/17106134

#SPJ1

5 0
2 years ago
What is the value of r^2 for the following data to three decimal places
BigorU [14]

B. 0.930 ~Apex ;) .....................................






















3 0
3 years ago
Read 2 more answers
Purchasing A regional survey found that 70% of all families who indicated an intention to buy a new car bought a new car within
zheka24 [161]

Answer:

If a family chosen at random bought a car, we need to find the probability that the family had not previously indicated an intention to buy a car = P(I'|B) = 0.3362

Step-by-step explanation:

Let the event that a family that intends to buy a car be I

Let the event that a family does not intend to buy a car be I'

Let the event that a family buys a car in those 3 months be B

Let the event that a family does not buy a car in those 3 months be B'

Given,

P(B|I) = 0.70

P(B|I') = 0.10

P(I) = 0.22

P(I') = 1 - P(I) = 1 - 0.22 = 0.78

If a family chosen at random bought a car, we need to find the probability that the family had not previously indicated an intention to buy a car = P(I'|B)

The conditional probability P(A|B), is given as

P(A|B) = P(A n B) ÷ P(B)

So,

P(B|I) = P(B n I) ÷ P(I)

P(B n I) = P(B|I) × P(I) = 0.70 × 0.22 = 0.154

P(B|I') = P(B n I') ÷ P(I')

P(B n I') = P(B|I') × P(I') = 0.10 × 0.78 = 0.078

P(B) = P(B n I) + P(B n I') = 0.154 + 0.078 = 0.232

P(B') = 1 - 0.232 = 0.768

P(I'|B) = P(B n I') ÷ P(B)

= 0.078 ÷ 0.232 = 0.3362

Hope this Helps!!!

8 0
3 years ago
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