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lisov135 [29]
3 years ago
10

Select all the fractions that are equivalent to 4/5. Use the area models to help.

Mathematics
1 answer:
FrozenT [24]3 years ago
6 0

Answer:

8/10 and 12/15

Step-by-step explanation:

The first area model shows that 4 of the 5 blocks are filled.

The second area model shows that 8 of the 10 blocks are filled.

The third area model shows that 12 of the 15 blocks are filled.

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A three inch diameter pulley on an electric motor that runs at 1800
Bezzdna [24]

Answer:

a) 3 inch pulley: 11,309.7 radians/min

6) 6 inch pulley: 5654.7 radians/min

b) 900 RPM (revolutions per minute)

Step-by-step explanation:

Hi!

When a pulley wirh radius R rotantes an angle θ, the arc length travelled by a point on its rim is Rθ.  Then the tangential speed V is related to angular speed  ω as:

V=R\omega

When you connect two pulleys with a belt, if the belt doesn't slip, each point of the belt has the same speed as each point in the rim of both pulleys: Then, both pulleys have the same tangential speed:

\omega_1 R_1 = \omega_2 R_2\\

\omega_2 = \omega_1 \frac{R_1}{R_2} =1800RPM* \frac{3}{6}= 900RPM

We need to convert RPM to radias per minute. One revolution is 2π radians, then:

\omega_1 = 1800*2\pi \frac{radians}{min} = 11,309.7\frac{radians}{min}

\omega_2 = 5654.7 \frac{radians}{min}

The saw rotates with the same angular speed as the 6 inch pulley: 900RPM

3 0
4 years ago
Enter <,>,= to make the problem true -19 5/6 _ -20 1/6
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Answer:

>

..................................................................

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Linear Inequalities & Systems of Inequalities
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Answer:

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3 years ago
How will the circumference of the circle change if it is dilated by a scale factor of 4?
Stolb23 [73]

The circumference of a circle has the formula:

C = 2 π r

 

Now when it is dilated by a factor of 4, this only means that the radius is also multiplied by a factor of 4, therefore the new circumference is:

C’ = 2 π (4 r)

C’ = 8 π r

So it also grows 4 times.

 

Answer:

<span>The circumference will be 4 times greater than the original.</span>

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