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sweet [91]
3 years ago
7

Plot points 0, 3 on y axis use slope of 2 to graph another point through the two points

Mathematics
1 answer:
Nikolay [14]3 years ago
7 0
Check the picture below

you could, also go 2/1 to the left-hand-side

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Clare is paid 90$ for 5 hours of work. At this rate, how many seconds dose it take for her to earn 25 cents?
mrs_skeptik [129]

Answer:

84 seconds

Step-by-step explanation:

Because if you divide all of that you would get that answer

3 0
3 years ago
What is the SCALE FACTOR (in decimal form) for a ratio of 6:15?
deff fn [24]
0.4
.....




......
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5 0
3 years ago
Read 2 more answers
What is the equation of a circle with center (-3, -1) that contains the point (1, 2)?
Leno4ka [110]
So, we know the center is at -3,-1, ok

hmmm what's the radius anyway?   well, we know that there's a point at 1,2 that is on the circle's path...hmmmm what's the distance from the center to that point?  well, is the radius, let's check then.

\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
&({{ -3}}\quad ,&{{ -1}})\quad 
%  (c,d)
&({{ 1}}\quad ,&{{ 2}})
\end{array}\qquad 
%  distance value
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}
\\\\\\
r=\sqrt{[1-(-3)]^2+[2-(-1)]^2}\implies r=\sqrt{(1+3)^2+(2+1)^2}
\\\\\\
r=\sqrt{16+9}\implies r=\sqrt{25}\implies r=5

so, what's the equation of a circle with center at -3, -1 and a radius of 5?

\bf \textit{equation of a circle}\\\\ 
(x-{{ h}})^2+(y-{{ k}})^2={{ r}}^2
\qquad 
\begin{array}{lllll}
center\ (&{{ h}},&{{\quad  k}})\qquad 
radius=&{{ r}}\\
&-3&-1&5
\end{array} 
\\\\\\\
[x-(-3)]^2+[y-(-1)]^2=5^2\implies (x+3)^2+(y+1)^2=25
7 0
3 years ago
If is parallel to , which statement must be true?
tatuchka [14]
The answer is B because they can’t interest but perpendicular can
8 0
3 years ago
Find an equation of the line containing (-3,4) and having slope -2. If this line contains the points (a,8) and (5,b), find a and
larisa [96]

Answer:

Step-by-step explanation:

Remark

The slope intercept line is written as y = mx + b in it's general form.

You can get the slope, m, immediately because it is given as -2

So far what you have is y = -2x + b

y intercept

To get the y intercept, use the point (-3 , 4)

x = - 3

y = 4

4 = -2*(-3) + b

4 = 6 + b                 Subtract 6 from both sides

4 - 6 = 6-6 + b

b = - 2

Line

y = -2x - 2

(a,8)

y = -2a - 2

8 = -2a - 2              Add 2 to both sides

8 +2 = -2a -2+2     Combine

10 = - 2a                 Divide by - 2

10/-2 = a

a = -5

(5,b)

y = -2x - 2

x = 5

y = b

b = -2*5 - 2

b = -10 - 2

b = - 12

6 0
2 years ago
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