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Murrr4er [49]
3 years ago
11

1.You roll a fair six sided die twice.What is the probability of rolling a 3 and then a 5? A.1/3 B.1/6 C.1/12 D.1/36 2.What is t

he number of possible outcomes if two marbles are picked out of a bag that contains three red marbles and three blue marbles? [Note: Order does not matter.] A) 2 B) 3 C) 4 D) 6
Mathematics
1 answer:
GarryVolchara [31]3 years ago
6 0

Answer:

1. The correct answer is D) 1/36

Step-by-step explanation:

WE can tell this because the chance of rolling either is 1/6. To find the total probability we multiply those together.

1/6 * 1/6 = 1/36

You might be interested in
1. When given the expression 5^3, what should you do to solve?
UNO [17]

Answer:

its b) 5×5×5

Step-by-step explanation:

a) 5×3 is 15

b) 5×5×5 is 5^3 or in simple form its 125

c) 3×3×3×3×3 = 3^5 or in simple form its 243

You should solve 5^3 as

= 5×5×5

= 125

Plzz mark me as brainliest :)★

5 0
3 years ago
NEED HELP ASAP<br> Solve the equation or inequality for the unknown number. Show your work.
amid [387]

Answer:

5

Step-by-step explanation:

3(14+x) = 57

42 +3x = 57

3x = 15

x = 5

6 0
3 years ago
Q16. Find x^2 + 1/x^2 , if x + 1/x = 3
erica [24]

Answer:

2 \times  x \times \frac{1}{x}  =  2 \\  {x}^{2}   +  {y }^{2}  + 2xy =  {(x + y)}^{2} \\ {x}^{2}  +  \frac{1}{ {x}^{2} }  + 2 = {(x +  \frac{1}{x} })^{2}  =  {3}^{2}  = 9

8 0
2 years ago
The question is...................
Norma-Jean [14]
B is dilated by a factor of 5
5 0
3 years ago
Solve the compound inequality,
Feliz [49]

Answer:

\large\boxed{y\in(-6,\ \infty)}

Step-by-step explanation:

(1)\\2y-2>-14\qquad\text{add 2 to both sides}\\\\2y-2+2>-14+2\\\\2y>-12\qquad\text{divide both sides by 2}\\\\\dfrac{2y}{2}>\dfrac{-12}{2}\\\\y>-6

(2)\\\\4y-4\geq12\qquad\text{add 4 to both sides}\\\\4y-4+4\geq12+4\\\\4y\geq16\qquad\text{divide both sides by 4}\\\\\dfrac{4y}{4}\geq\dfrac{16}{4}\\\\y\geq4

\text{From (1) and (2) we have:}\\\\y>-6\ or\ y\geq4\to y\in(-6,\ \infty)\ \cup\ [4,\ \infty)\Rightarrow y\in(-6,\ \infty)

7 0
3 years ago
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