3 years ago

Expand the expression and combine like terms: 2(−14+r)−(−3r−5)

Mathematics

1 answer:

Serggg [28]3 years ago

4 0

2r-20 is the answer combining the like terms and solving.

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In circle O, what is m∠MAJ? °

mr_godi [17]

See the attached figure.

m ∠KAJ = 170° & m ∠LAM = 80°

We should know that :

m ∠KAJ + m ∠LAM + m ∠KAL + m ∠MAJ = 360°

∴ m ∠KAL + m ∠MAJ = 360° - (m ∠KAJ + m ∠LAM)

∴ m ∠KAL + m ∠MAJ = 360° - (170°+80°) = 360° - 250° = 110°

But : m ∠KAL = m ∠MAJ ⇒⇒⇒ Opposite angles.

∴ m ∠MAJ + m ∠MAJ = 110°

∴ 2 * m ∠MAJ = 110°

∴ m ∠MAJ = 110° ÷ 2 = 55°

So, the answer is : m ∠MAJ = 55°

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2 years ago

What is 59% of 14 m?

sergiy2304 [10]

That would be 8.26 meters.

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3 years ago

The temperatures at 6:00 am one morning in four cities are given below.

Andre45 [30]

Answer:

-9

Step-by-step explanation:

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2 years ago

AngleRQT is a straight angle. What are m angleRQS and m angleTQS? m angleRQS=

lara31 [8.8K]

$\widehat{RQS}+\widehat{TQS}=\widehat{RQT}\\\Leftrightarrow 9x + 1 + 7x + 3 = 180 \\ \widehat{RQS}+\widehat{TQS}=\widehat{RQT}\\\Leftrightarrow 16x = 176\Leftrightarrow x = 11 \\ \Rightarrow \widehat{RQS} = 9 \times 11 + 1 = 100° \: \wedge \: \widehat{TQS} = 7 \times 11 + 3 = 80°$

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3 years ago

Sz – [32 – (10z + 2)]

Dmitry_Shevchenko [17]

Sz－[32－(10z＋2)]
＝Sz－(32－10z－2)
＝Sz－(30－10z)
＝Sz－30＋10z

Hope my answer helped u :)

5 0

3 years ago