Answer: 471.24 (with 3.14 as pi)
Step-by-step explanation:
Volume of cylinder = pi*r^2*height
Radius = 10/2 = 5
Pi*25^2*6 = 471.24
Given:
Desmond deposits $ 50 monthly.
Yearly he deposits = $50×12 = $ 600
Rate of interest compounded monthly = 4.7%
To find the amount he will receive after 10 years and the rate of change the value of his account after 10 years.
Formula
![A = P(1+\frac{r}{(n)(100)} )^{nt}](https://tex.z-dn.net/?f=A%20%3D%20P%281%2B%5Cfrac%7Br%7D%7B%28n%29%28100%29%7D%20%29%5E%7Bnt%7D)
where,
A be the final amount
P be the principal
r be the rate of interest
t be the time and
n be the number of times the interest is compounded.
Now,
Taking,
P = 600, r = 4.7, n = 12, t = 10 we get,
![A = 600(1+\frac{4.7}{(12)(100)}) ^{(12)(10)}](https://tex.z-dn.net/?f=A%20%3D%20600%281%2B%5Cfrac%7B4.7%7D%7B%2812%29%28100%29%7D%29%20%5E%7B%2812%29%2810%29%7D)
or, ![A = 600(1.0039)^{120}](https://tex.z-dn.net/?f=A%20%3D%20600%281.0039%29%5E%7B120%7D)
or, ![A = 959.1](https://tex.z-dn.net/?f=A%20%3D%20959.1)
Now,
At starting he has $ 600
At the end of 10 years he will be having $ 959.1
So,
The amount of change in his account = $ (959.1-600) = $ 359.1
Therefore the rate of change = ![(\frac{359.1}{600} )(100) %](https://tex.z-dn.net/?f=%28%5Cfrac%7B359.1%7D%7B600%7D%20%29%28100%29%20%25)
= 59.85%
Hence,
a) His account will contain $ 959.1 after 10 years.
b) The rate of change in his account is 59.85% after 10 years.
Answer: b
Step-by-step explanation:
I'll try to explain in the simplest way possible:
Total cost for a single widget: $32 + $44 = $76 for one widget.
So, since we know the cost of one widget is $76, then the price of 350 widgets would be = $76 x 350 = $26,600.