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just olya [345]
3 years ago
14

What coordinates exist on the line y=2x+4

Mathematics
1 answer:
DaniilM [7]3 years ago
6 0

First put the values of  x and y into y=2x+4


(1,-2)    -2= 2(1) - 4 = -2
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Will give brainliest.
earnstyle [38]

Answer:

They added 8 to each side,     --8 is +8    so we need to subtract - from each side not add 8 to each side

Step-by-step explanation:

We have a slope and a point

We can use point slope form

y-y1 = m(x-x1)

y--8 = -6(x-2)    

y+8 = -6(x-2)

Distribute the -6

y+8 = -6x+12

Subtract 8 from each side

      ERROR in the students work

They added 8 to each side,     --8 is +8    so we need to subtract - from each side not add 8 to each side

y+8-8 = -6x+12-8

y = -6x+4


8 0
4 years ago
Read 2 more answers
Suppose that we want to generate the outcome of the flip of a fair coin, but that all we have at our disposal is a biased coin w
Goshia [24]

Answer:

Step-by-step explanation:

Given that;

the following procedure for accomplishing our task are:

1. Flip the coin.

2. Flip the coin again.

From here will know that the coin is first flipped twice

3. If both flips land on heads or both land on tails, it implies that we return to step 1 to start again. this makes the flip to be insignificant since both flips land on heads or both land on tails

But if the outcomes of the two flip are different i.e they did not land on both heads or both did not land on tails , then we will consider such an outcome.

Let the probability of head = p

so P(head) = p

the probability of tail be = (1 - p)

This kind of probability follows a conditional distribution and the probability  of getting heads is :

P( \{Tails, Heads\})|\{Tails, Heads,( Heads ,Tails)\})

= \dfrac{P( \{Tails, Heads\})  \cap \{Tails, Heads,( Heads ,Tails)\})}{  {P( \{Tails, Heads,( Heads ,Tails)\}}}

= \dfrac{P( \{Tails, Heads\}) }{  {P( \{Tails, Heads,( Heads ,Tails)\}}}

= \dfrac{P( \{Tails, Heads\}) } {  {P( Tails, Heads) +P( Heads ,Tails)}}

=\dfrac{(1-p)*p}{(1-p)*p+p*(1-p)}

=\dfrac{(1-p)*p}{2(1-p)*p}

=\dfrac{1}{2}

Thus; the probability of getting heads is \dfrac{1}{2} which typically implies that the coin is fair

(b) Could we use a simpler procedure that continues to flip the coin until the last two flips are different and then lets the result be the outcome of the final flip?

For a fair coin (0<p<1) , it's certain that both heads and tails at the end of the flip.

The procedure that is talked about in (b) illustrates that the procedure gives head if and only if the first flip comes out tail with probability 1 - p.

Likewise , the procedure gives tail if and and only if the first flip comes out head with probability of  p.

In essence, NO, procedure (b) does not give a fair coin flip outcome.

5 0
3 years ago
Diego wants to buy a new TV. The TV costs $649.99 right now. She has a coupon for 20% off any
Vlad [161]

Answer:

$519.00

Step-by-step explanation:

The 20% off coupon takes $130.00 off the original price of the TV.

 $649.99

- $130.00 =

  $519.00

6 0
3 years ago
What are the questions
kenny6666 [7]

The answers are, from 7 to 14,


11/3

50/6

49/6

18/8

11/2

7/4

26/5

14/6


3 0
3 years ago
4) A dozen cookies cost $18.75. Twenty cookies cost $25.50. Which has the lower unit price?
Sedbober [7]

Answer:

Twenty cookies deal

Step-by-step explanation:

A dozen cookies cost 18.75. A dozen is exactly 12. If you divide 18.75 by 12 you should get the unit price which is about $1.56 for each cookie. For 25.50 you just divide it by 20 and you should get about 1.20 which makes it a better deal.

4 0
3 years ago
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