The size of chicken at the form would be 111.8 inches.
Step-by-step explanation:
Given that,
The average height of cow = x1 = 4 feet 5 inches
x1 = 4 x 12 + 5 = 53 inches (12 inches in a feet)
The average height of chicken = y1 = 13 inches.
The height of cow statue at form = x2 = 38 feet
x2 = 38 x 12 = 456 inches
The height of chicken statue = y2 = ?
For this, the ratio of height in both the scenarios would be the same. Therefore,
x1/y1 = x2/y2
now, by putting the values
53/13 = 456/y2
y2 = (456x 13) / 53
y2 = 111.8 inches
Hence, the size of chicken at the form would be 111.8 inches.
Answer:
19
Step-by-step explanation:
5x² – 3x + 5
Substitute 2 in for x
5(2)² - 3(2) + 5
Solve exponents first
5(4) - 3(2) + 5
Solve/multiply parenthesis
20 - 6 + 5
Add and subtract
19
Hope this helps :)
Answer:
-3
Step-by-step explanation:
Let the number be x
2 + 9x= - 25
9x= - 27
x= - 3
JK is equal to 9, so c
You have to set up a proportion, i’m going to use LM and DC
i’m going from the biggest quad to smallest quad, while setting up a proportion. 20/15=12/x
cross multiply, getting 20x=180
then divide both sides by 20, getting 9!
RST=54
PQR=54
POR=144
I’m sorry if these arent correct, but I tried my best