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Iteru [2.4K]
2 years ago
7

Which expression will find the price of the jacket after applying the sale look at the pic below

Mathematics
1 answer:
horsena [70]2 years ago
5 0
I don’t know about this one ... ima say b ..
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Find the surface area and volume of each figure. Round each answer to the nearest hundredth.
Llana [10]

Answer: Surface area is equal to 200cm^{2}

Volume is equal to 333.33cm^{3}

Step-by-step explanation:

First, let's do surface area.

The surface area of a pyramid is equal to 1/2(perimeter of base)(lateral height) + area of the base

The perimeter of the base is 10(4) = 40; as the base is a square with a side length of 10.

The lateral height is given as 5 cm.

The area of the base is 10(10) = 100.

We can plug those numbers into the equation to get 1/2(40)(5) + 100, which comes out to be 200cm^{2}.

Now for volume.

The volume of a pyramid is equal to 1/3(area of the base)(height).

We already have the area of the base, which is 100.

The height is given as 10 cm.

Plugging those numbers into the equation, we get 1/3(100)(10), which is 1000/3 or about 333.33cm^{3}.

Hope this helps!

6 0
3 years ago
What is the mixed number for 24/3
galben [10]
The mixed number is 8
8 0
3 years ago
Read 2 more answers
How do you use distributive property for 12(52)-12(62)
ololo11 [35]

Answer:

-120 , split it into diferent parts.

Step-by-step explanation:

12 (52) - 12 (62) = ?

12 x 52 = 624

12 x 62 = 744

624 - 744 = -120

3 0
3 years ago
What’s the 5th term is 2,14,98
iragen [17]

\bold{\huge{\orange{\underline{ Solution }}}}

<h3><u>Correct </u><u>Question </u><u>:</u><u>-</u></h3>

What is the 5th term of an AP 2 , 14 ....98 .

<h3><u>Given </u><u>:</u><u>-</u><u> </u></h3>

<u>We </u><u>have </u><u> </u><u>AP</u><u>, </u>

  • \sf{ 2 , 14 ,.... 98 }
  • <u>AP </u><u>is </u><u>the </u><u>arithmetic </u><u>progression </u><u>or </u><u>a </u><u>sequence </u><u>of </u><u>numbers </u><u>in </u><u>which </u><u>succeeding </u><u>number </u><u>is </u><u>differ </u><u>from </u><u>preceeding </u><u>number </u><u>by </u><u>a </u><u>common </u><u>value</u><u>. </u>

<h3><u>Solution </u><u>:</u><u>-</u></h3>

<u>We </u><u>have </u><u>an </u><u>AP </u><u>:</u><u>-</u><u> </u><u>2</u><u> </u><u>,</u><u> </u><u>1</u><u>4</u><u> </u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>9</u><u>8</u>

<u>Therefore</u><u>, </u>

  • \sf{a1\: or \:1st\: term = 2 }
  • \sf{a2 \:or \:2nd\: term = 14 }
  • \sf{an \:or\: last\: term = 98}

<u>Here</u><u>, </u>

Common difference of an AP

\sf{ a2 - a1 }

\sf{ = 14 - 2}

\sf{ = 12}

Thus, The common difference is 12

<u>Now</u><u>, </u>

We know that,

\sf{an = a1 + ( n - 1 )d}

\sf{a5 = 2 + ( 5 - 1 )12}

\sf{a5 = 2 + 4 × 12}

\sf{a5 = 2 + 48}

\sf{\red{a5 = 50}}

Hence, The 5th term of given AP is 50

4 0
2 years ago
Help ASAP do both questions for 10 points
zlopas [31]

Answer:

Step-by-step explanation:

I'm guessing A and J. Makes the most sense.

5 0
2 years ago
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