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3 years ago

13

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.

2 answers:

AysviL [449]3 years ago

6 0

Answer:

Hypotenuse legs

6 units arrowBoth 5 units, 1 unit

5 units arrowBoth 2 units, 3 units

8 units arrowBoth 5 units, 2 units

3 units arrowBoth 1 unit, 2 unit

Step-by-step explanation:

i got this because if u add

5+1= 6 units

2+3=5 units

5+2=8 units

1+2=3 units

Allushta [10]3 years ago

5 0

Answer

what the person above me said i think

Step-by-step explanation

im not sure tho

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3 years ago

Which expression is equivalent to sqrt8x^7y^8? assume x>0

Ilia_Sergeevich [38]

Answer:

$\sqrt{8x^7y^8$ $= 2x^3y^4 * \sqrt{2x}$

Step-by-step explanation:

Given

$\sqrt{8x^7y^8$

Required

Evaluate

$\sqrt{8x^7y^8$

Separate each factor with multiplication sign

$\sqrt{8*x^7*y^8$

Express 8 as 4 * 2 and $x^7$ as $x^6 * x$

$\sqrt{4 * 2 *x^6 * x*y^8$

Split each factor

$\sqrt{4} * \sqrt{2} *\sqrt{x^6} * \sqrt{x}*\sqrt{y^8}$

Evaluate $\sqrt4$

$2 * \sqrt{2} *\sqrt{x^6} * \sqrt{x}*\sqrt{y^8}$

Apply law of indices:

$2 * \sqrt{2} * x^{6*\frac{1}{2}} * \sqrt{x} * y^{8*\frac{1}{2}}$

$2 * \sqrt{2} * x^3 * \sqrt{x} * y^4$

Reorder

$2* x^3 * y^4 * \sqrt{2} * \sqrt{x}$

$2x^3y^4 * \sqrt{2} * \sqrt{x}$

$2x^3y^4 * \sqrt{2*x}$

$2x^3y^4 * \sqrt{2x}$

$2x^3y^4 \sqrt {2x$

Hence:

$\sqrt{8x^7y^8$ $= 2x^3y^4 * \sqrt{2x}$

8 0

3 years ago

Read 2 more answers