3 years ago

Two numbers have a difference of 28. What is the sum of their squares if it is a minimum?

Mathematics

1 answer:

IRISSAK [1]3 years ago

6 0

Answer:

Now the square of x is x^2 and the square of x+ 28 is (x+28)^2.

The sum of the squares is x^2 + (x+ 28)^2.

x^2 + (x+ 28)^2

= x^2 + x^2 + 28^2 + 56x

= 2x^2 + 28^2 + 56x

Now let f(x) = 2x^2 + 28^2 + 56x

Step-by-step explanation:

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