The distance formula is:

We are given two points in the form (x,y), so plug in the values to the distance formula:

Next we can simplify. We know that 12-12 is 0, so we can drop it from the equation, as it will not affect our answer. Also, we know that -10-15 is -25:

The square and square root cancel each other out leaving us with 25.
The answer is 25.
The answer is : x= -y/3+2
X^2-6x+7=0
-b +/- sqrt b^2-4ac all over 2a
a=1 b= -6 and c=7
6+/- sqrt 36-4×1×7 all over 2×1
6+/- sqrt 8 all over 2
6+/- 2sqrt2 all over 2
reduce
3+/- sqrrt2
Cross multiplying:-
cot^2 x = (csc x+ 1)(csc x + 1)
also cot^2 x = csc^2 x - 1 = (csc x + 1)(csc x - 1) (Known Identitiy)
so the equation is not an identity
6x² + 2x - 20 = 0
3(2x² + x - 10) = 0
3[(2x² - 4x + 5x - 10)] = 0
3[2x(x - 2) + 5(x - 2)] = 0
3(2x + 5)(x - 2) = 0
3=0, 2x + 5 = 0, x - 2 = 0 (Note: 3=0 is false so disregard that equation)
x =
, x = 2
Answer: x = {
, 2}