21.0 yd^2 i THINK good luck
Answer: (a) 0.344578
(b) 0.211855
Step-by-step explanation: Let X represent Jill's score and Let Y represent Jack's score.
Jill's scores are approximately normally distributed with mean 170 and standard deviation 20 implies :
X ≈(170 ,
)
Also , since Jack's scores are approximately normally distributed with mean 160 and standard deviation, it implies
Y ≈ ( 160 ,
).
It is given that their scores are independent which means that the outcome one one will not affect the outcome of the other, we the have:
Y - X ≈ N(-10 ,
+
)
Y - X ≈ N(-10 ,625 )
Also , Y + X ≈ N ( 330 , 625 )
(a) We need to find the approximate probability that Jack's score is higher , that is
P ( Y > X)
=P(Y - X >0)
= P (
> ![\frac{10}{\sqrt{625} }](https://tex.z-dn.net/?f=%5Cfrac%7B10%7D%7B%5Csqrt%7B625%7D%20%7D)
= 1 - Ф(
)
= 1 - Ф(
)
= 1 - Ф ( 0.4)
= 1 - 0.655422
= 0.344578
P ( Y > X) ≈ 0.345
(b) We need to calculate the approximate probability that their total score is above 350 , that is
P ( X + Y > 350)
= P (
>
)
= 1 - Ф(
)
= 1 - Ф ( 0.8)
= 1 - 0.788145
= 0.211855
P ( X + Y > 350)≈ 0.212
Answer:
It is B - Because some applicants volunteer and meet the GPA requirements, the events are not mutually exclusive.Thus, the probability is 65%.
>3
Answer:
-8 < 8
Step-by-step explanation:
(-8) is smaller than 8...because for a value to be bigger...it has to be ahead of the other value(that its being compared to)...going in the positive direction of the numberline
A+b+c=130
a,b,c ip cu 2,3,4
2a=3b=4c=k
a=k/2
b=k/3
c=k/4
k/2 + k/3+ k/4= 130 aducem la acelasi numitor (12)
6k+4k+3k=1560
13k=1560
k=120
a=120/2=60
b=120/3=40
c=120/4=30