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Novay_Z [31]
3 years ago
8

Can someone explain by steps on how to do this

Mathematics
1 answer:
sleet_krkn [62]3 years ago
6 0

Answer:

8\sqrt{3}

Step-by-step explanation:

This is a special right triangle with angle measures 90-60-30 degrees

The side lengths are like the following :

The side length that sees 90 degrees is represented with x

The side length that sees 60 degrees is represented with x\sqrt{3}

The side length that sees 30 degrees is represented with 2x

the side that sees 90 degrees is given as 16 so x = 8 and so  a = 8\sqrt{3}

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Let a, b, c be the lengths of sides of a triangle; a=4.8, b=0.23, and c is a whole number. Find c.
BaLLatris [955]

\sqrt{4.8 {}^2{ +0.23 {}^{2} } }
If you solve it, the answer will be

C= 4.80

Seeing as its supposed to be a whole number, you will round up, so it will be 5
4 0
3 years ago
Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s). Consider the eq
Deffense [45]

To solve for x in terms of b, simply treat b as a number, and solve for x as usual: first of all, we expand the left hand side:

-2bx+10 = 16

Subtract 10 from both sides:

-2bx = 6

Divide both sides by -2b:

x = \cfrac{6}{-2b} = \cfrac{-3}{b}

This means that in particular, if we set b= 3, we have

x = \cfrac{-3}{3} = -1

5 0
3 years ago
Which equation represents the line passing through the point (4, −5) that is parallel to the line x + 2y = 10?
SVETLANKA909090 [29]

Answer:

get photomath it will answer this

4 0
3 years ago
The graph of $y=ax^2+bx+c$ passes through points $(0,5)$, $(1,10)$, and $(2,19)$. Find $a+b+c$.
MAVERICK [17]

Answer:

a+b+c=10

Step-by-step explanation:

We are given that the graph of the equation:

y=ax^2+bx+c

Passes through the three points (0, 5), (1, 10), and (2, 19).

And we want to find the value of (<em>a</em> + <em>b</em> + <em>c</em>).

First, since the graph passes through (0, 5), its <em>y-</em>intercept or <em>c</em> is 5. Hence:

y=ax^2+bx+5

Next, since the graph passes through (1, 10), when <em>x</em> = 1, <em>y</em> = 10. Substitute:

(10)=a(1)^2+b(1)+5

Simplify:

5=a+b

The point (2, 19) tells us that when <em>x</em> = 2, <em>y</em> = 19. Substitute:

(19)=a(2)^2+b(2)+5

Simplify:

14=4a+2b

This yields a system of equations:

\begin{cases} 5 = a + b \\ 14 = 4a + 2b\end{cases}

Solve the system. We can do so using elimination (or any other method you prefer). Multiply the first equation by negative two:

-10=-2a-2b

Add the two equations together:

(-10)+(14)=(-2a+4a)+(-2b+2b)

Combine like terms:

4 = 2a

Hence:

a=2

Using the first equation:

5=(2)+b\Rightarrow b=3

Therefore, our equation is:

y=2x^2+3x+5

Thus, the value of (<em>a</em> + <em>b</em> + <em>c</em>) will be:

a+b+c = (2) + (3) + (5) = 10

7 0
3 years ago
A basket contains apples and oranges in the ratio of 4:1. How many apples are there if the total amount of fruits is 40?
algol13

Answer:32

Step-by-step explanation:

  • u fist find the total ratio 4+1 =5

then the ratio belonging to apple is four

so u divide 4 by 5 then multiply to the total no of fruit

and that will give u 32

4 0
4 years ago
Read 2 more answers
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