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vaieri [72.5K]
3 years ago
9

How do I solve this problem

Mathematics
1 answer:
yuradex [85]3 years ago
5 0
Is that the full
question, is their a picture with it
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Hey can anybody give me a teachers answer key on dis lessons
KATRIN_1 [288]
Hm maybe look up the name of the document and put pdf answers
3 0
3 years ago
A stock market fell 40 points each day for
Montano1993 [528]

Answer: -120

Step-by-step explanation:

-40 X 3 = -120

7 0
2 years ago
Find they area of a regular hexagon with a side length of 10 inches
Vitek1552 [10]
A≈259.81in²

I hope this helped!!
3 0
3 years ago
Please include work!
geniusboy [140]

Answer:

x = ± 4

y = - 2

Step-by-step explanation:

y = 0.5x² - 10 ------------------------(I)

y = -x² + 14   ------------------------(II)

Substitute the y value in equation (II)

    0.5x² - 10  = -x² + 14           {Add x² to both sides}            

0.5x² + x² -10 = 14                  {combine like terms}

       1.5x² - 10 = 14                   {Add 10 to both sides}

               1.5x² = 14 + 10

                1.5x² = 24         {Divide both sides by 1.5}

               1.5x²/1.5 = 24/1.5

                       x² = 16

                      x = ±4

Substitute x = 4 in (I)

y = 0.5 * 4² - 10

 = 0.5*16 - 10

 = 8- 10

y = -2

Substitute x = -4 in (I)

y = 0.5 * (-4)² - 10

 = 0.5*16 - 10

 = 8- 10

y = -2

5 0
3 years ago
Foe the AP given by a1,a2,......,an,...with non zero common difference, the equation satisfied are
user100 [1]
The given sequence is
a₁, a₂, ..., a_{n}

Because the given sequence is an arithmetic progression (AP), the equation satisfied is
a_{n}=a_{1}+(n-1)d
where
d =  the common difference.

The common difference may be determined as
d = a₂ - a₁

The common difference is the difference between successive terms, therefore
d = a₃ - a₂ = a₄ - a₃, and so on..

The sum of the first n terms is
S_{n}= \frac{n}{2} (a_{1}+a_{n})

Example:
For the arithmetic sequence
1,3,5, ..., 
the common difference is d= 3 - 1 = 2.
The n-th term is
a_{n}=1+2(n-1)

For example, the 10-term is
a₁₀ = 1 + (10-1)*2 = 19
Th sum of th first 10 terms is
S₁₀ = (10/2)*(1 + 19) = 100



8 0
3 years ago
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