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PIT_PIT [208]
2 years ago
8

Recall the quotient rule

Mathematics
1 answer:
Ghella [55]2 years ago
6 0

Answer:

The quotient rule says that the derivative of the quotient is "the derivative of the top times the bottom, minus the top times the derivative of the bottom, all divided by the bottom squared"..... ... We simply recall that the quotient f/g is the product of f and the reciprocal of g. Hope it helps

Step-by-step explanation:

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Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used. Match each verbal description of a sequen
galben [10]

Answer:

I think the question is wrong so, I will try and explain with some right questions

Step-by-step explanation:

We are give 6 sequences to analyse

1. an = 3 · (4)n - 1

2. an = 4 · (2)n - 1

3. an = 2 · (3)n - 1

4. an = 4 + 2(n - 1)

5. an = 2 + 3(n - 1)

6. an = 3 + 4(n - 1)

1. This is the correct sequence

an=3•(4)^(n-1)

If this is an

Let know an+1, the next term

an+1=3•(4)^(n+1-1)

an+1=3•(4)^n

There fore

Common ratio an+1/an

r= 3•(4)^n/3•(4)^n-1

r= (4)^(n-n+1)

r=4^1

r= 4, then the common ratio is 4

Then

First term is when n=1

an=3•(4)^(n-1)

a1=3•(4)^(1-1)

a1=3•(4)^0=3.4^0

a1=3

The first term is 3 and the common ratio is 4, it is a G.P

2. This is the correct sequence

an=4•(2)^(n-1)

Therefore, let find an+1

an+1=4•(2)^(n+1-1)

an+1= 4•2ⁿ

Common ratio=an+1/an

r=4•2ⁿ/4•(2)^(n-1)

r=2^(n-n+1)

r=2¹=2

Then the common ratio is 2,

The first term is when n =1

an=4•(2)^(n-1)

a1=4•(2)^(1-1)

a1=4•(2)^0

a1=4

It is geometric progression with first term 4 and common ratio 2.

3. This is the correct sequence

an=2•(3)^(n-1)

Therefore, let find an+1

an+1=2•(3)^(n+1-1)

an+1= 2•3ⁿ

Common ratio=an+1/an

r=2•3ⁿ/2•(3)^(n-1)

r=3^(n-n+1)

r=3¹=3

Then the common ratio is 3,

The first term is when n =1

an=2•(3)^(n-1)

a1=2•(3)^(1-1)

a1=2•(3)^0

a1=2

It is geometric progression with first term 2 and common ratio 3.

4. I think this correct sequence so we will use it.

an = 4 + 2(n - 1)

Let find an+1

an+1= 4+2(n+1-1)

an+1= 4+2n

This is not GP

Let find common difference(d) which is an+1 - an

d=an+1-an

d=4+2n-(4+2(n-1))

d=4+2n-4-2(n-1)

d=4+2n-4-2n+2

d=2.

The common difference is 2

Now, the first term is when n=1

an=4+2(n-1)

a1=4+2(1-1)

a1=4+2(0)

a1=4

This is an arithmetic progression of common difference 2 and first term 4.

5. I think this correct sequence so we will use it.

an = 2 + 3(n - 1)

Let find an+1

an+1= 2+3(n+1-1)

an+1= 2+3n

This is not GP

Let find common difference(d) which is an+1 - an

d=an+1-an

d=2+3n-(2+3(n-1))

d=2+3n-2-3(n-1)

d=2+3n-2-3n+3

d=3.

The common difference is 3

Now, the first term is when n=1

an=2+3(n-1)

a1=2+3(1-1)

a1=2+3(0)

a1=2

This is an arithmetic progression of common difference 3 and first term 2.

6. I think this correct sequence so we will use it.

an = 3 + 4(n - 1)

Let find an+1

an+1= 3+4(n+1-1)

an+1= 3+4n

This is not GP

Let find common difference(d) which is an+1 - an

d=an+1-an

d=3+4n-(3+4(n-1))

d=3+4n-3-4(n-1)

d=3+4n-3-4n+4

d=4.

The common difference is 4

Now, the first term is when n=1

an=3+4(n-1)

a1=3+4(1-1)

a1=3+4(0)

a1=3

This is an arithmetic progression of common difference 4 and first term 3.

5 0
3 years ago
A survey showed that 35% of the students prefer plain white milk over chocolate milk. If the school has 1200 students. How many
vodomira [7]

Answer:

The number of students who prefer chocolate milk is 780 .

Step-by-step explanation:

Given as :

The total number of students in the school = 1200

The percentage of students who prefer plain white milk = 35 %

Let the number of students who prefer chocolate milk = x

Now, ∵ The percentage of students who prefer plain white milk = 35 %

∴ The percentage of students who prefer chocolate milk = 100 % - 35 % = 65%

So , As The number of  students who prefer chocolate milk = x

Or, 65 % of total number of students in school = x

So, x = \frac{65}{100} × 1200

or, x = \frac{65\times 1200 }{100}

∴  x = 780

So, the number of students who prefer chocolate milk = x = 780

And  students who prefer plain white milk = 1200 - x = 1200 - 780 = 420

Hence, The number of students who prefer chocolate milk is 780 . Answer

4 0
3 years ago
Evaluate each expression if m = 3, n = 7, and p = 9
katrin2010 [14]

Answer:

27

Step-by-step explanation:

<u><em>First, you would do 7+2 to get 9 and then multiply it by itself to get 81. Next, you divide 81 by 3 to get 27.</em></u>

4 0
2 years ago
Read 2 more answers
ASAP HELPPPPPPPPPPPPPPPP!!!!!!!!!!!!!!!
melomori [17]

Step-by-step explanation:

  1. 90-27=63°
  2. <2
  3. <2,<4
  4. 360°
3 0
2 years ago
Read 2 more answers
The grocery store is having a candy sale. Originally, a candy bar was $1.50. The
dangina [55]

The markdown rate is 66.7%.

<h3>Markdown rate</h3>

Using this formula

Markdown rate= Change in price/original price×100

Let plug in the formula

Markdown rate=$1.50-$0.50/$1.50

Markdown rate=$1.00/$1.50×100

Markdown rate=66.66%

Markdown rate=66.7% (Approximately)

Inconclusion the markdown rate is 66.7%.

Learn more about markdown rate here:brainly.com/question/1153322

8 0
2 years ago
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