Question

Find an equation of the line is the perpendicular to 30X-5Y=5 and passes through the point (0,-3).

Answer 1

Answer:

$y = (\frac{-1}{6})x - 3$

Step-by-step explanation:

Given line = 30x - 5y = 5 or y = 6x + 1

so, the slope of the given line is 6.

now, let the line which is perpendicular to the given line be y = mx + c

where,

m = slope of the line

c = constant

As we know, if two lines are perpendicular to each other, the value of product of there slopes are -1.

so, slope of given line × slope of perpendicular line = -1

⇒ 6(m) = -1

⇒ m = $\frac{-1}{6}$

By substitutiong the value of m in the equation, we get;

⇒ $y = (\frac{-1}{6})x + c$

For c,

as the point (0,-3) passes through the line, we get;

⇒ $-3 = (\frac{-1}{6})(0) + c$

⇒ $c = -3$

Hence,

The line which is perpendicular to the given line and passes through (0,-3) is  $y = (\frac{-1}{6})x - 3$ .

Answer 2

Answer:

it is C

Step-by-step explanation:

i did the test got 100