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rewona [7]
4 years ago
9

PLEASE HELP ON TIMER!!!!!

Mathematics
1 answer:
Lesechka [4]4 years ago
6 0

Answer:

8

Step-by-step explanation:

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Sin(2x+30°)=1 <br> Tìm x <br> Cảm ơn vì giúp đỡ
Pie

Answer:

Step-by-step explanation:

This question is asking us to find where sin(2x + 30) has a sin of 1. If you look at the unit circle, 90 degrees has a sin of 1. Mathematically, it will be solved like this (begin by taking the inverse sin of both sides):

sin^{-1}[sin(2x+30)]=sin^{-1}(1)

On the left, the inverse sin "undoes" or cancels the sin, leaving us with

2x + 30 = sin⁻¹(1)

The right side is asking us what angle has a sin of 1, which is 90. Sub that into the right side:

2x + 30 = 90 and

2x = 60 so

x = 30

You're welcome!

4 0
3 years ago
What is the length of DE?
vladimir1956 [14]

Answer, 2.865.00

Step-by-step explanation: o D.7 x - OB. 8 -OA x- 14 x 12 + 84498  + DXE X

4 0
3 years ago
Which statement describes the behavior of the function f(x)=3x/4-x?
Oksana_A [137]

Answer:

The  graph approaches –3 as x approaches infinity. Option a is correct.

Step-by-step explanation:

The given function is

f(x)=\frac{3x}{4-x}

We have to find value of function as x approaches infinity. Take limit both sides as x approaches to infinity.

\lim_{x\rightarrow \infty}f(x)=\lim_{x\rightarrow \infty}\frac{3x}{4-x}

Taking x common from the denominator.

\lim_{x\rightarrow \infty}f(x)=\lim_{x\rightarrow \infty}\frac{3x}{x(\frac{4}{x}-1)}

Cancel out common factor x.

\lim_{x\rightarrow \infty}f(x)=\lim_{x\rightarrow \infty}\frac{3}{\frac{4}{x}-1}

Apply limits.

\lim_{x\rightarrow \infty}f(x)=\frac{3}{\frac{4}{\infty}-1}

\lim_{x\rightarrow \infty}f(x)=\frac{3}{0-1}

\lim_{x\rightarrow \infty}f(x)=-3

Therefore the  graph approaches –3 as x approaches infinity.

7 0
4 years ago
Read 2 more answers
3(2x+1) =-5-5+3x solve the problem ​
Firlakuza [10]

Answer:-3

Step-by-step explanation:

8 0
3 years ago
Find tenth term of the sequence (1,1,2,3,5,8,13)
garri49 [273]
This is what we call a Fibonacci sequence:

Notice that after the 1,1:

4th term =3 ==> 2+1

5th term =5 ==>3+2


6th term =8==> 5+3

7th term = 13==> 8+5

8th term =...........13+8 =21

9th term = ...........21+13 =34

10t=h term =........34+21 = 55

In short each number equal the sum of the 2 preceding number

7 0
4 years ago
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