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Rzqust [24]
3 years ago
7

A single household circuit is connected to three electrical outlets (all in parallel). The outlets are connected to three device

s: an 800-W electric kettle, a 60-W trouble light, and a 1,000-W toaster oven. If all three appliances operate at the same time, will the 15-amp fuse of the circuit trip? yes or no ?
Physics
2 answers:
natima [27]3 years ago
8 0

<span>Power (Watts) = Voltage (Volts) times the Current in (Amps). 
</span>so
<span>P=I*E Or
 (P/E) = I Or (P/I) = E </span>
<span>So a 2,000 W dryer operating at 240V will draw 8.3 Amps. </span>
<span>But a 2,000 W dryer operating at 120V will draw 16.7 Amps. </span>
so
<span> 800W + 60W +1,000W total 1,860W 
</span>applying formula
<span>Using (P/E) = I </span>
<span>1,860W/120V = 15.5A </span>
<span>yep, it could trip a 15.0 A breaker
hope it helps</span>
marishachu [46]3 years ago
7 0
The total power consumption when all three of them are turned on is 1,860 watts. Power=(voltage)x(current). If the service to the household is 120 volts, then the current will be 1860/120=15.5A, which the fuse or breaker will not allow, and they will blow/trip. If the house is in South America or Europe, and the mains service is 240 volts, then the current will be 1860/240= 7.75 Amp, and the fuse or breaker will be 'cool' with that.
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You are in charge of a cannon that exerts a force 11500 N on a cannon ball while the ball is in the barrel of the cannon. The le
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Answer:

m = 7.48 kg

Explanation:

force (f) = 11,500 N

length of barrel (s) = 1.7 m

angle above the ground = 49.3 degrees

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initial velocity (u) = 0 m/s

final velocity (v) = 72.3 m/s

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acceleration (a) = force / mass (m)

acceleration (a) = 11500 / m

applying the equation of motion v^{2} = u^{2} + 2as , we can get the mass

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m = 7.48 kg

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A string with linear density 0.500 g/m.

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So, The total energy as a function of  v^{2} _{y, max} = 7.5 x 10⁻⁴ v^{2} _{y, max}

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