the weight of the balloon is .030 * 10 = 0.3 N
the weight of the gas of volume v is 0.54*10 N
The lifting force of a volume of v m³ of displaced air is 1.29v N
so, we need
1.29*10*v = 0.3 + 0.54*10*v
or
1.29v = 0.03+0.54v
The EM spectrum has no limits. Any frequency you can imagine
is the frequency of some electromagnetic radiation somewhere.
The loudness of sound refer to how loud or soft a sound seems to a listener
The specific heat capacity of the substance is 
Explanation:
When an object of mass m is supplied with a certain amount of energy Q, its temperature increases according to the equation:

where
m is the mass of the object
is its specific heat capacity
is the increase in temperature of the object
In this problem, we have

m = 50 g

Therefore, we can solve for
to find its specific heat capacity:

Learn more about specific heat capacity:
brainly.com/question/3032746
brainly.com/question/4759369
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Answer:
C. Takes heat in, does work, and loses energy heat.
Explanation:
Heat engine is a system makes use of thermal energy (heat) to in order to do mechanical work.
This occurs by converting the heat into mechanical energy. This energy is then used to do work.
The key characteristic of a heat engine is that the substance with which work is done by, goes from a higher temperature to a lower temperature.
Hence, it loses heat as it does work.