The absolute error is 4 cubic inches. To find the absolute error, you simply subtract the two values.
The percent error is 10%. To find the percent error, we create a fraction out of the error and the actual value.
4 / 40 x 100 = 10%
Use PEMDAS with the first 3.
a. 3×(6÷5)
3×(1.2) [Parenthesis first]
3.6. [then multiply]
b. 3÷(5×6)
3÷(30) [Parenthesis first]
.1 [then divide]
c. (3×6)÷5
(18)÷5 [Parenthesis first]
3.6 [then divide]
d. 3×6÷5
18÷5 [Left to right]
3.6 [then divide]
Answer:
We conclude that If Tawnee increases the length and width of the playground by a scale factor of 2, the perimeter of the new playground will be twice the perimeter of the original playground.
Step-by-step explanation:
We know that the perimeter of a rectangle = 2(l+w)
i.e.
P = 2(l+w)
Here
Given that the length and width of the playground by a scale factor of 2
A scale factor of 2 means we need to multiply both length and width by 2.
i.e
P = 2× 2(l+w)
P' = 2 (2(l+w))
= 2P ∵ P = 2(l+w)
Therefore, we conclude that If Tawnee increases the length and width of the playground by a scale factor of 2, the perimeter of the new playground will be twice the perimeter of the original playground.
There are 120 blocks left.
Answer:
Step-by-step explanation:
let the length of rectangle=l units
width=9
p=2(l+9)
area=9l
9l=2(l+9)
9l=2l+18
7l=18
l=18/7 units
