If the older brother is 27...27/3=9...+10=19....and 27+19=46. So the math works out, the younger brother is 19.
A. (3,5) B. (-4,-3) C. (-4,4) D. (5,-3) E. (6,7) F. (-8,-8) G. (-2,7) H. (-2,-4) I. (3,-9) J. (1,0)
Answer:
24
Step-by-step explanation:
The question is saying, how many three digit numbers can be made from the digits 3, 4, 6, and 7 but there can't be two of the same digit in them. For example 346 fits the requirements, but 776 doesn't, because it has two 7s.
Okay, on to the problem:
We can do one digit at a time.
First digit:
There are 4 digits that we can choose from. (3, 4, 6, and 7)
Second digit:
No matter which digit we chose for the first digit, there is only going to be 3 of them left, because we already chose one, and you can't repeat that same digit. So there are 3 options.
Third digit:
Using the same logic, there are only 2 options left.
We have 4 choices for the first digit, 3 choices for the second, and 2 for the third.
Hence, this is 4 * 3 * 2 = 24 three-digit numbers that can be made.
Answer: 14th floor
Step-by-step explanation:
20 - 11 + 5 = 14
2304cubes(14^3 cm^3/cube)=6322176 cm^3
