Question

The bases of the trapezoid are 6 and 10. The height is 4. Find the area.

Answer 1

Answer:

$b. \ \boxed{32 \sq. \ units}$

Step-by-step explanation:

A trapezoid is a quadrilateral where at least one pair of opposite sides are parallel. In a trapezoid, the both parallel sides are known as the bases of the trapezoid. So we have two bases, namely, $b_{1}\,and\,b_{2}$. Also, the height $H$ of the trapezoid is the length between these two bases that's perpendicular to both sides. So the area of a trapezoid in terms of of $b_{1},b_{2}\:and\:H$ is:

$A=\frac{(b_{1}\text{+}b_{2})h}{2}$

Since:

$b_{1}=6, \ b_{2}=10, \ and \ H=4$

The area is:

$A=\frac{(6\text{+}10)4}{2}=\boxed{32 \sq. \ units}$