FOR Y
opposite angles - equal
angles in a quadrilateral are 360 degrees
68 + 68 = 136
360 - 136 = 224
224/2 = 112 degrees
angles on a straight line = 180 degrees
180 - 112 = 68
Y = 68
FOR X
angles on a straight line are 180 degrees
180 - 68 = 112 degrees
X=112 degrees
<h3>
Answer: 36 square units</h3>
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Explanation:
Draw a horizontal line to cut the figure into a rectangle on top and a triangle down below.
The rectangle has length and width of 6 and 4 (horizontal and vertical components respectively). The area of this rectangle is 6*4 = 24 square units.
The triangle has a base of 6 and a height of 4. The base and height of any triangle are always perpendicular.
The area of the triangle is base*height/2 = 6*4/2 = 24/2 = 12 square units. If you were to cut out half of the triangle and rearrange things, you'll find that a rectangle can be formed. This rectangle is half in area that of the first rectangle we found. This is why we divide by 2 when finding the area of the triangle.
Once you know the two sub-areas, we add them up to get the overall area: 24+12 = 36 square units.
Answer:
It's a parallelogram, angles B and D, and A and C are congruent, lines AB and DC, and BC and AD are congruent.
Step-by-step explanation:
Distribute the .25 to get .25x + 1 - 3 = 28
Then simplify to get .25x - 2 = 28
Move the two to the right to get .25x = 30
Then divide to leave x: 30 / .25 = 120
X = 120
Given that quadrilateral QRST is a square.
Each angle of a square is of 90 degrees.
Angle <RQT is also an angle of 90 degrees.
We also given angle RQT = 3x - 6.
So, we can setup an equation as 3x-6 =90.
Now, we need to solve the equation for x.
6 is being subtracted from left side.
We always apply reverse operation. Reverse operation of subtraction is addition.
So, adding 6 on both sides of the equation, we get
3x-6+6 =90+6.
3x = 96.
3 is being multipied with x, in order to remove that 3, we need to apply reverse operation of multiplication.
So, dividing both sides by 3.
x=32 (final answer).
