ABCD is a rectangle. Find the length of each diagonal...
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The area and perimeter of the triangle is 2/5 square units and (2√10 + 4√5) / 5 units
<h3>Perimeter and area of the triangle giving the equation of a line</h3>First we will plot the giving lines, determine the point of intersection and then use the Pythagoras theorem to determine the dimension of the right triangle.
From the given equation of the lines, the points of intersection of the line are (x₁, y₁) = (- 0.4, 5.2), (x₂, y₂) = (-0.8, 4.4) and (x₃, y₃) = (0, 4)
For the base
b² = c² -a²
b = √(-0.8)² + (4 - 4.4)²
b = 2√5 / 5
For the height
h = √((- 0.4) - (- 0.8))² + (5.2 - 4.4)²
height = 2√5 / 5
For the hypotenuse
r = √2 · b
r = 2√10 / 5
<h3>Determine the Perimeter and area</h3>Perimeter = s1+s2+s3
Perimeter = 2√5 / 5 + 2√5 / 5 + 2√10 / 5
Perimeter = (2√10 + 4√5) / 5 units
<u>For the area</u>
area = 1/2* base * height
A = 0.5 · (2√5 / 5) · (2√5 / 5)
A = 2/5 square units
Hence the area and perimeter of the triangle is 2/5 square units and (2√10 + 4√5) / 5 units
Learn more on area and perimeter of triangles here: brainly.com/question/21511715
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