The tower is 61.65 meters tall.
<u>SOLUTION:
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Given that, a pole that is 2.5 m tall casts a shadow that is 1.47 m long.
At the same time, a nearby tower casts a shadow that is 36.25 m long.
We have to find height of the tower.
Now, we know that,

Then, (let it be) n meter tall
36.25 long shadow
So, by cross multiplication method,

This can be written as,

Cross multiplications steps: (To find Single Variable)
- Multiply the numerator of the left-hand fraction by the denominator of the right-hand fraction.
- Multiply the numerator of the right-hand fraction by the denominator of the left-hand fraction.
- Set the two products equal to each other.
- Solve for the variable.
Answer: b
Step-by-step explanation: The graph shows that the maxiumum x is -1 and it can go lower. You plug them in and b is the right answer.
Assuming width=diameter
diameter/2=radius
area=hpir^2
w=d=2
d/2=2/2=1=r
h=6
area=6pi1^2
area=6pi1
area=6pi
aprox pi=3.141592
area=18.85 cm³
The answer is y=3(x-1)^2+6
Substitute all x in the equation to 1.6
∴6-4(1.6)=-1.6/4
∴-0.4=-0.4
∴Yes