-x^2=23 in standard form
1 answer:
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Multiplying eqn no. two with 4 we add it up with eqn 1.
When
So, x = - 10/17 and y = - 42/17.
Answer:
2500 Square meters
Step-by-step explanation:
Given the garden area (as a function of its width) as:
The maximum possible area occurs when we maximize the area. To do this, we take the derivative, set it equal to zero and solve for w.
A'(w)=-2w+100
-2w+100=0
-2w=-100
w=50 meters
Since Marquise has 200 meters of fencing to build a rectangular garden,
Perimeter of the proposed garden=200 meters
Perimeter=2(l+w)
2(l+50)=200
2l+100=200
2l=200-100=100
l=50 meters
The dimensions that will yield the maximum area are therefore:
Length =50 meters
Width=50 meters
Maximum Area Possible =50 X 50 =<u>2500 square meters.</u>
Answer:
p < -32
Step-by-step explanation:
<em>Given:</em> p/-8 + 9 > 13
<em>Rewrite:</em> + 9 > 13
<em>Subtract 9 from both sides:</em> > 4
<em>Move the negative (it is a fraction): </em> > 4
<em>Multiply both sides by 8:</em> -p > 32
<em>Times by -1 (-p -> -1p): </em>p > -32
<em>Flip the sign (multiplied by a negative): </em>p < -32
Hope this helps, have a nice day :D