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Bas_tet [7]
2 years ago
15

What is true about anglemsr? it must be acute. it must be a right angle. it must be equal to anglemrh. it must be equal to angle

rms.
Mathematics
1 answer:
NARA [144]2 years ago
7 0

From the given diagram <msr is a right angle (equal to 90 degrees) and <mrh is acute since it is less than 90degrees.

<h3>Properties ofa rhombus</h3>

The given diagram is a rhombus that has the following properties

  • Opposite side are equal
  • All the sides are congruent
  • The opposite angles are equal
  • The sum of the adjacent angles are supplementary

From the figure shown, we can see that;

<msr is a right angle (equal to 90 degrees)

<mrh is acute since it is less than 90degrees.

Learn more on rhombus here: brainly.com/question/88523

#SPJ1

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Answer:

wkldd

Step-by-step explanation:

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Please help me find the area for this hexagon (please show work to) ,:)
kvasek [131]

Check the picture below.

so the area of the hexagon is really just the area of two isosceles trapezoids.

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2 years ago
Describe how you know that this is a proportional relationship
Deffense [45]

Answer:

(Some textbooks describe a proportional relationship by saying that " y varies proportionally with x " or that " y is directly proportional to x .") ... This means that as x increases, y increases and as x decreases, y decreases-and that the ratio between them always stays the same.

<h2>Hopefully u will satisfy with my answer..!!</h2><h2>Please Mark on brainleast please..!!</h2><h2>Have a nice day ahead dear..!!</h2>
4 0
3 years ago
An adult ticket to a museum costs 3$ more than a children’s ticket. When 200 adult tickets and 100 children tickets are sold, th
antiseptic1488 [7]

The cost of children’s ticket is $ 5

<h3><u>Solution:</u></h3>

Let "c" be the cost of one children ticket

Let "a" be the cost of one adult ticket

Given that adult ticket to a museum costs 3$ more than a children’s ticket

<em>Cost of one adult ticket = 3 + cost of one children ticket</em>

a = 3 + c  ------ eqn 1

<em><u>Given that 200 adult tickets and 100 children tickets are sold, the total revenue is $2100</u></em>

200 adult tickets x cost of one adult ticket + 100 children tickets x cost of one children ticket = 2100

200 \times a + 100 \times c = 2100

200a + 100c = 2100 ------ eqn 2

<em><u>Let us solve eqn 1 and eqn 2 to find values of "a" and "c"</u></em>

Substitute eqn 1 in eqn 2

200(3 + c) + 100c = 2100

600 + 200c + 100c = 2100

600 + 300c = 2100

300c = 1500

<h3>c = 5</h3>

Thus the cost of children’s ticket is $ 5

6 0
3 years ago
Help me with this please :)
shtirl [24]

Answer:

second option

G(3 , -4) ; H(8 , 1)

Step-by-step explanation:

For the line GH  to be a median, the point G must have the intermediate value at x and at y between points A and B, and the point H must have the intermediate value at x and at y between points A and B

G = (Ax + Bx)/2 , (Ay + By)/2

G = (3 + 3)/2 , (-9 + 1)/2

G = 6/2 , -8/2

G = (3 , -4)

H = (Cx + Bx)/2 , (Cy + By)/2

H = (13 + 3)/2 , (1 + 1)/2

H = 16/2 , 2/2

H = (8 , 1)

This is because for a medium to be the point p has to be right in the middle of the other 2 vertices

7 0
3 years ago
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