Answer:
5.5
Step-by-step explanation:
2 times 3 is 6 then but to the other side so plus 6 then You have 2y=11
then you dived it by two so 11 dived by 2 and you get 5.5
There are nine possible combinations as follows: bb, bc, bt, cb, cc, ct, tb, tc, tt, each having a probability of 1/9. The four combinations with a cab exactly one time are: bc, cb, ct, tc. Therefore the probability that she'll use a cab exactly one time is: 4/9.
Answer:
10.75
Step-by-step explanation:
The cost of an adult ticket is £6 more than that of a child ticket, so will be shown by c+6.
Now, we are told that the cost of four child tickets and two adult tickets is £40.50, so we can put this in an equation and solve for c:
(c+6)+(c+6)+c+c+c+c=40.50
6c+12=40.50
6c=28.50
c=4.75
so, a childs ticket is 4.75
now to find the cost of an adult ticket you add 6,
4.75 + 6
= 10.75
No Solution
x=2+ Square root of x-2
-2
x-2= Square root of x-2
2s cancel out.
x = Square root of x
Or you can just graph it and see no solutions
<u>Answer </u><u>:</u><u>-</u>
Given inequality ,
- -5x +3y > 12
- 3y > 5x + 12
- y > 5/3x + 12/3
- y > 5/3x + 4
From the options ,
<u>When </u><u>x </u><u>is </u><u>3</u><u> </u><u>and </u><u>y </u><u>=</u><u> </u><u>9</u>
- y >1* 5 + 4
- y > 5 +4
- 9> 9 ( Not possible )
<u>When</u><u> </u><u>x </u><u>is </u><u>-</u><u>5</u><u> </u><u>y</u><u> </u><u>is </u><u>5</u><u> </u>
- y > 5/3*-5 + 4
- y > -8.3 + 4
- 5 > -3.7 ( Possible )
<u>When </u><u>x </u><u>is </u><u>3</u><u> </u><u>y </u><u>is </u><u>-</u><u>6</u><u> </u>
- y > 5 + 4
- -6 > 9 ( Not possible )
<u>When </u><u>x </u><u>is </u><u>-</u><u>2</u><u> </u><u>y </u><u>is </u><u>-</u><u>5</u><u> </u>
- y > -3.33 + 4
- -5 > -0.67 ( Possible )
<u>When </u><u>x </u><u>is </u><u>2</u><u> </u><u>y </u><u>is </u><u>8</u><u> </u>
- y > 3.33 + 4
- 8 > 7.77 ( possible )
<u>When</u><u> </u><u>x </u><u>is </u><u>-</u><u>6</u><u> </u><u>y </u><u>is </u><u>0</u><u> </u>
- y > -10 +4
- 0 > -6 ( possible )