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3 years ago

14

When the price of Xis RM4 and the price of Y is RM10, which of the following combinations would be the intercept of axes

1 answer:

ss7ja [257]3 years ago

4 0

I would say C but I’m not completely 100% sure

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Can anyone help? 25 points

damaskus [11]

Answer:

w>-5/12

Step-by-step explanation:

w > 1/3 - 3/4 = 4/ 12 - 9/ 12

w> -5/12

7 0

4 years ago

Read 2 more answers

5(3x + 7) = 20 – 2(x + 1)

Temka [501]

the answer to this is x= -1

5 0

3 years ago

Read 2 more answers

(4 7/8) (8 1/10) ( 3) HELP ASAP!!!!!!

Tom [10]

Answer:

8.4

Step-by-step explanation:

(7/8) (4) = 3.5

(1/10) (8) = 0.8

3.5 × 0.8 × 3 = 8.4

Hope this helps.

7 0

3 years ago

Given f(x)=3x+1, find f(x+5)

soldier1979 [14.2K]

Answer:

f(x+5)=3x+16

Step-by-step explanation:

lets name " x+5" T

so f(T)=3T+1

now use "x+5" replace T

now its f(x+5)=3(x+5)+1=3x+15+1=3x+16

7 0

4 years ago

Sometimes a change of variable can be used to convert a differential equation y′=f(t,y) into a separable equation. One common ch

enot [183]

Answer:

$y=\frac{-7t^2+22t-7}{7t-22}$

Step-by-step explanation:

We are given that

Initial value problem

$y'=(t+y)^2-1$ , y(3)=4

Substitute the value $z=t+y$

When t=3 and y=4 then

z=3+4=7

$y'=z^2-1$

Differentiate z w.r.t t

Then, we get

$\frac{dz}{dt}=1+y'$

$z'=1+z^2-1=z^2$

$z^{-2}dz=dt$

Integrate on both sides

$-\frac{1}{z}dz=t+C$

$z=-\frac{1}{t+C}$

Substitute t=3 and z=7

Then, we get

$7=-\frac{1}{3+C}$

$21+7C=-1$

$7C=-1-21=-22$

$C=-\frac{22}{7}$

Substitute the value of C then we get

$z=-\frac{1}{t-\frac{22}{7}}$

$z=\frac{-7}{7t-22}$

$y=z-t$

$y=\frac{-7}{7t-22}-t$

$y=\frac{-7-7t^2+22t}{7t-22}$

$y=\frac{-7t^2+22t-7}{7t-22}$

8 0

4 years ago