Step-by-step explanation:
RS bisects PQ at T. PQ bisects RS at T.
<u>prove</u>: Triangle PTS congruent Triangle QTR
<h3>Statements..............................Reasons</h3>
(1) RS bisects PQ at T.................(1) Given
(2) PQ bisects RS at T.................(2) Given
(3) angle PST ≅ angle QRT........(3) supplements of congruent angles
(4) TS ≅ TR......................(4) Converse of Base Angles Theorem
(5) angle PTS ≅ angle QTR.........(5) Subtraction Property of Equality
(6) Triangle PTS ≅ Triangle QTR...(6) Angle side angle
Hope it's help you..... ^_^❤️
Answer:
f(-5)= 28
Step-by-step explanation:
The function is:
f(x)= x^2-2x-7
To find the answer put the value of -5 for all x's.
f(x)= x^2-2x-7
f(-5)=(-5)^2 - 2(-5)-7
f(-5)=25+10-7
f(-5)=35-7
f(-5)= 28 ...
6,042 is thousand and 1.012 is thousandths <span />
I think the best property to use is electronegativity since that is how much it attracts/wants electrons. The larger the difference in electronegativity is between two atoms, the stronger the ionic bond will be. This is also why two atoms need to have a minimum difference between the electronegativity to be considered ionic and not covalent.
X²+y²-8x+12y+27=0
x²+y²-8x+12y=-27
x²-8x +y²+12y = -27
x²-8x+16 + y+12y+36 = -27+16+36=25
(x-4)² + (y+6)² = 25
a circle centered at (4,-6) with a radius of 5
