Question

Julie has 5 cherry lollipops,1 lime lollipops, and 2 grape lollipops in a bag. She is going to select one lollipop, replace the lollipop in the bag, and then select a second one. What is the probability that Julie will select a cherry lollipop and then a lollipop other than grape?
a.)6/8

b.)11/16

c.)15/32

d.)10/64

Answer 1

Answer: $\dfrac{15}{32}$

Step-by-step explanation:

Given : The number of cherry lollipop = 5

The total number of lollipop = 8

the number of lollipops other than grape =6

The probability of selecting a cherry lollipop is given by :_

$\text{P(Cherry)}=\dfrac{5}{8}$

The probability of selecting a lollipop other than grape is given by :_

$\text{P(Other than grape)}=\dfrac{6}{8}$

Since, there is replacement , then the events are independent of each other.

Now, the probability that Julie will select a cherry lollipop and then a lollipop other than grape is given by :-

$\text{P(Cherry and other than grape)}=\dfrac{5}{8}\times\dfrac{6}{8}=\dfrac{15}{32}$

Hence, the required probability =$\dfrac{15}{32}$