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lbvjy [14]
2 years ago
5

a. A 2017 poll found that 56​% of college students were very confident that their major will lead to a good job. If 15 college s

tudents are chosen at​ random, what's the probability that 13 of them were very confident their major would lead to a good​ job? Let a success be a college student being very confident their major would lead to a good job.
Mathematics
1 answer:
lesya [120]2 years ago
8 0

Answer:

0.01083 or 1.083%

Step-by-step explanation:

This problem can be modeled as a binomial probability model with probability of success p = 0.56.

The probability of x=13 successes (a college student being very confident their major would lead to a good job) in a number of trials of n=15 is:

P(X=x) = \frac{n!}{(n-x)!x!} *p^x*(1-p)^{n-x}\\P(X=13) = \frac{15!}{(15-13)!13!} *0.56^{13}*(1-0.56)^{15-13}\\P(X=13) = 0.01083=1.083\%

The probability is 0.01083 or 1.083%.

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The answer is £64.89.

Step by Step:

Take the original price multiplied by 0.03 ( the percent of a booking fee ) and add those amounts together.

Equation: 63 + 1.89 = 64.89
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3 years ago
What is the percent change in the price of a gallon of gas, to the nearest whole percent?
Hatshy [7]

Answer: 3.499 now 3.079 is correct

8 0
2 years ago
PLEASE HELP
Licemer1 [7]

Answer:

35 dimes and 60 nickels

Step-by-step explanation:

let d = # of dimes and n = # of nickels

We know that Timmy has a total of 95 coins, consisting of dimes and nickels

So d + n = 95

The total value of his bank is $6.50

A dime is worth $0.10 and a nickel is work $0.05

So 0.10d + 0.05n = $6.50

Note that we've just created a system of equations that we can solve

We have the two equations

0.10d + 0.05n = 6.50 and d + n = 95

There are many different methods we can use to solve this system but the easiest way in this situation is probably going to be the substitution method.

First we are going to want to rearrange the terms of the second equations so that one of the variables are defined.

d + n = 95

- subtract d from both sides -

n = 95 - d

We now defined "n"

Now that we have defined one of the variables we can plug in ( or substitute ) the value of it into the other equation. Once we substitute it we can solve for the other variable.

0.10d + 0.05n = 6.50

n = 95 - d

0.10d + 0.05(95 - d) = 6.50

we now solve for d

0.10d + 0.05(95 - d) = 6.50

step 1 distribute the 0.05

0.05 * 95 = 4.75 and 0.05 * -d = -0.05d

0.10d + 4.75 - 0.05d = 6.50

step 2 combine like terms 0.10d  - 0.05d = 0.05d

0.05d + 4.75 = 6.50

step 3 subtract 4.75 from both sides

0.05d = 1.75

step 4 divide both sides by 0.05

0.05d / 0.05 = d and 1.75 / 0.05 = 35

d = 35

Now that we have found the value of one variable we can plug it into one of the equations and solve for the other variable ( note that the equation that we use does not matter, we will acquire the same answer )

d + n = 95

d = 35

35 + n = 95

subtract 35 from both sides

n = 60

We can conclude that he has 35 dimes and 60 nickels

4 0
2 years ago
List the first 10 multiples for each number 3,4,7
notka56 [123]

Answer:

Step-by-step explanation:

3- 3, 6, 9, 12, 15, 18, 21, 24, 27, 30

4- 4, 8, 12, 16, 20, 24, 28, 32, 36, 40

7- 7, 14, 21, 28, 35, 42, 49, 56, 63, 70

HOPE IT HELPED

3 0
3 years ago
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Answer:

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Step-by-step explanation:

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