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lbvjy [14]
3 years ago
5

a. A 2017 poll found that 56​% of college students were very confident that their major will lead to a good job. If 15 college s

tudents are chosen at​ random, what's the probability that 13 of them were very confident their major would lead to a good​ job? Let a success be a college student being very confident their major would lead to a good job.
Mathematics
1 answer:
lesya [120]3 years ago
8 0

Answer:

0.01083 or 1.083%

Step-by-step explanation:

This problem can be modeled as a binomial probability model with probability of success p = 0.56.

The probability of x=13 successes (a college student being very confident their major would lead to a good job) in a number of trials of n=15 is:

P(X=x) = \frac{n!}{(n-x)!x!} *p^x*(1-p)^{n-x}\\P(X=13) = \frac{15!}{(15-13)!13!} *0.56^{13}*(1-0.56)^{15-13}\\P(X=13) = 0.01083=1.083\%

The probability is 0.01083 or 1.083%.

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Hello!

We are told that n and m are parallel.
The angle that measures 105 degrees is supplementary with the alternate interior angle of the angle which measures (3x - 18) degrees. Supplementary angles add to equal 180 degrees, so we can make an equation by first finding the measure of the alternate interior angle.

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The alternate interior angle measures 75 degrees, so we can set that equal to 3x - 18 to solve for x since alternate interior angles are congruent.

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