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abruzzese [7]
3 years ago
11

PLEASE HELP ME !! Carter has 3 statues of various sizes in his garden. Statue A is one foot taller than statue B. Statue is one-

half of a foot taller than statue B. A) write an algebraic expression for the total combined height of statue A and c. (equations for statues A and C) B) If the total combined height of the 3 statues is 10 feet, find the height of statue B in inches.

Mathematics
1 answer:
Serjik [45]3 years ago
7 0

Answer:


Step-by-step explanation:


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Imagine a pond. In it sits one lilypad, which reproduces once a day. Each of its offspring also reproduces once a day, doubling
sergeinik [125]

Answer: On the 29th day

Step-by-step explanation:

According to this problem, no lilypad dies and the lilypads always reproduce, so we can apply the following reasoning.

On the first day there is only 1 lilypad in the pond. On the second day, the lilypad from the first reproduces, so there are 2 lilypads. On day 3, the 2 lilypads from the second day reproduce, so there are 2×2=4 lilypads. Similarly, on day 4 there are 8 lilypads. Following this pattern, on day 30 there are 2×N lilypads, where N is the number of lilypads on day 29.

The pond is full on the 30th day, when there are 2×N lilypads, so it is half-full when it has N lilypads, that is, on the 29th day. Actually, there are 2^{30} lilypads on the 30th, and 2^{29} lilypads on the 29th. This can be deduced multiplying succesively by 2.  

4 0
3 years ago
Help me asap please
lapo4ka [179]

6^4

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8 0
3 years ago
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Simplify (9k6 + 8k4 - 6k2)(4k2 - 5)​
Tasya [4]

Answer:

36k^8-13k^6-64k^4+30k^2

Step-by-step explanation:

36k^8-13k^6-64k^4+30k^2\\9k^6*(4k^2-5)+8k^4*(4k^2-5)-6k^2*(4x^2-5)\\36k^8-45k^6+8k^4*(4k^2-5)-6k^2*(4x^2-5)\\36k^8-45k^6+32k^6-40k^4-6k^2*(4x^2-5)\\36k^8-45k^6+32k^6-40k^4-24k^4+30k^2\\36k^8-13k^6-40k^4-24k^4+30k^2\\36k^8-13k^6-64k^4+30k^2

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A car travels a distance of 540 km in 6 hours what speed did he travel at
SVETLANKA909090 [29]

Speed = Distance /  time

Speed = 540 km / 6 hours

Speed = 90 km/hr.

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3 years ago
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