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notka56 [123]
3 years ago
15

Find the distance between (-8,7) and (13,-1)​

Mathematics
1 answer:
grin007 [14]3 years ago
6 0

Answer:

22.4722

Step-by-step explanation:

To answer this question we need to use the distance formula. The distance formula is as follows:

d = \sqrt{(x2 - x1)^2+(y2 - y1)^2}

Now, let's identify what each variable is:

x2 = 13

x1 = -8

y2 = -1

y1 = 7

Next, let's put these into the equation:

d = \sqrt{(13 - (-8))^2 + (-1 -7)^2}

Time to solve the equation:

d = \sqrt{(21)^2+(-8)^2} \\d = \sqrt{441 + 64} \\d = \sqrt{505} \\d = 22.4722

Therefore, the distance between the points of (-8,7) and (13,1) is 22.4722.

<em>I hope this helps!!</em>

<em>- Kay :)</em>

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Answer:

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Step-by-step explanation:

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3 years ago
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Answer:

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Step-by-step explanation:

From the question,

s = d/t................. Equation 1

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make d the subject of the equation,

d = s×t.................... Equation 2

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3 years ago
Find the value of x.
umka2103 [35]

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Hey there!

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If $x$, $y$, and $z$ are positive integers such that $6xyz+30xy+21xz+2yz+105x+10y+7z=812$, find $x+y+z$.
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Step-by-step explanation:

When we simplify we get $$z(6xy+21x+2y+7)+30xy+105x+10y=812.$$

Then we continue to factor to get: (z+5)(6xy+21x+2y+7)&=847.

We then see that we can factor (6xy+21x+2y+7) into (z+5)(3x+1)(2y+7)&=847.

we then do the prime factorization of 847, which i think is,  7*11*11. we have to find the numbers that multiply to 847 and then plug them into z+5, 3x=1,2y+7.

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We also see that 3x+1=11 so we see that x=10/3 (which wont work).

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4 years ago
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Answer:

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