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3 years ago

Find the distance between (-8,7) and (13,-1)

Mathematics

1 answer:

grin007 [14]3 years ago

6 0

Answer:

22.4722

Step-by-step explanation:

To answer this question we need to use the distance formula. The distance formula is as follows:

$d = \sqrt{(x2 - x1)^2+(y2 - y1)^2}$

Now, let's identify what each variable is:

x2 = 13

x1 = -8

y2 = -1

y1 = 7

Next, let's put these into the equation:

$d = \sqrt{(13 - (-8))^2 + (-1 -7)^2}$

Time to solve the equation:

$d = \sqrt{(21)^2+(-8)^2} \\d = \sqrt{441 + 64} \\d = \sqrt{505} \\d = 22.4722$

Therefore, the distance between the points of (-8,7) and (13,1) is 22.4722.

I hope this helps!!

- Kay :)

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220

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4 years ago

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4x - 3y = 15 2x + 2y = 4 what is the solution of the system of equations?

klio [65]

Answer:

System of Linear Equations entered :

[1] 4x - 3y = 15

[2] 2x + 2y = 4

Step-by-step explanation:

// Solve equation [2] for the variable y

[2] 2y = -2x + 4

[2] y = -x + 2

// Plug this in for variable y in equation [1]

[1] 4x - 3•(-x +2) = 15

[1] 7x = 21

// Solve equation [1] for the variable x

[1] 7x = 21

[1] x = 3

// By now we know this much :

x = 3

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// Use the x value to solve for y

y = -(3)+2 = -1

Solution :

{x,y} = {3,-1}

6 0

3 years ago

Find a polynomial with the following zeros. HELPPPP ASAPPP

Pavlova-9 [17]

Answer:

x³ - 4x² + 2x + 4 = 0

Here's how I solved this:

You start off by rewriting the zeros into factors:

1 - √3 → x = 1 - √3 → (x - 1 - √3)

2 → x = 2 → (x - 2)

1 + √3 → x = 1 + √3 → (x - 1 + √3)

Now you want to multiply the factors together:

(x - 1 - √3) · (x - 2) · (x - 1 + √3)

- Multiply the first two factors together -

(x - 1 - √3) · (x - 2)

↓

(x · x - x · 2 - √3 · x + √3 · 2 - x + 2)

- Combine like terms and simplify -

(x · x - x · 2 - √3 · x + √3 · 2 - x + 2)

↓

(x² - 3x - √3 · x + 2√3 + 2)

- Now multiply the third factor -

(x² - 3x - √3 · x + 2√3 + 2)(x - 1 + √3)

↓

(x² · x + x² · √3 - x² - 3x · x - 3x · √3 + 3x - √3 · xx - √3 · x · √3 +√3 · x + 2 · √3 · x + 2 · √3 · √3 - 2 · √3 + 2x + 2 · √3 - 2)

↓

(x³ + x² · √3 - x² - 3x² - 3x · √3 + 3x - √3 + 3x - √3 * x² - x · 3 + √3 · x + 2 · √3 · x + 2 · 3 - 2 × √3 + 2x + 2 √3 - 2)

- Combine like terms and simplify -

(x³ + x² · √3 - x² - 3x² - 3x · √3 + 3x - √3 + 3x - √3 * x² - x · 3 + √3 · x + 2 · √3 · x + 2 · 3 - 2 × √3 + 2x + 2 √3 - 2)

↓

x³ - 4x² + 2x + 4

--------------------------------------------------------------------------------------------------------------

And there we get our solution: x³ - 4x² + 2x + 4

8 0

2 years ago

This is used for the next few questions: The rating for the new scary movie has a scale of 0 to 10. The average response was tha

boyakko [2]

Answer:

The percentage that of people who gave the movie a rating between 6.8 and 8.8

P(6.8≤X≤8.8) = 83.9≅ 84 percentage

Step-by-step explanation:

Step(i):-

Mean of the Population = 8.3 points

Standard deviation of the Population = 0.5 points

Let 'X' be the random variable in normal distribution

Let X = 6.8

$Z = \frac{x-mean}{S.D} = \frac{6.8-8.3}{0.5} = -3$

Let X = 8.8

$Z = \frac{x-mean}{S.D} = \frac{8.8-8.3}{0.5} = 1$

The probability that of people who gave the movie a rating between 6.8 and 8.8

P(6.8≤X≤8.8) = P(-3≤Z≤1)

= P(Z≤1)- P(Z≤-3)

= 0.5 + A(1) - ( 0.5 -A(-3))

= A(1) + A(3) (∵A(-3)=A(3)

= 0.3413 +0.4986 (∵ From Normal table)

= 0.8399

Conclusion:-

The percentage that of people who gave the movie a rating between 6.8 and 8.8

P(6.8≤X≤8.8) = 83.9≅ 84 percentage

6 0

4 years ago

Find the distance between (-8,7) and (13,-1)​

Find the distance between (-8,7) and (13,-1)