Question

Identify the vertex of y = x^2 + 4x + 5

Answer 1

Answer:

D. (-2,1)

Step-by-step explanation:

we have

$y=x^2+4x+5$

This is the equation of a vertical parabola open upward The vertex represent a maximum

Convert the quadratic equation in vertex form

$y=a(x-h)^2+k$

where

(h,k) is the vertex

Complete the square

$y=(x^2+4x+2^2)+5-2^2$

$y=(x^2+4x+4)+5-4$

$y=(x^2+4x+4)+1$

Rewrite as perfect squares

$y=(x+2)^2+1$

The vertex is the point (-2,1)