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3 years ago

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A farmer ordered 3/4 ton of soil. He wants to divide it evenly into 8 flower beds. How much will he have for each bed?

1 answer:

Fed [463]3 years ago

3 0

Answer:

3/32 tons

Step-by-step explanation:

3/4 divided by 8

3/4 divided by 8/1

3/4 times 1/8

3/32 tons per flower pot

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62 newspapers in 2 piles = newspapers per pile

Zina [86]

Answer:

Step-by-step explanation:

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1 year ago

Cole is an urban planner. He wants to create a small scale drawing of a city block. The block is a square with sides of length 1

Mashcka [7]

So if 11 units on the map is 5m in real life, the scale is 11 units= 5m
But we need 100m.
We would need 20 groups of 5m to get 100m.
So we would need 20 groups of 11 units, which is 220 units.
So, on the scale drawing, the square would need to be 220 units by 220 units.

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3 years ago

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A truck rental company rents a truck for one day by charging $39 plus $1 per mile. Write a linear model that relates the cost C,

Anika [276]

Answer:

1m+39c=y

Step-by-step explanation:

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3 years ago

a cell phone company plans to market a new smartphone. they have already sold 612 units durning the first week of the campaign.

Vadim26 [7]

The first term is 612.

The common ratio is 1.08 and

The recursive rule is $a_{n} = a^{n-1} \times r$

<u>Step-by-step explanation:</u>

the question to the problem is to write the values of the first term, common ratio, and expression for the recursive rule.

<u>The first term :</u>

In geometric sequence, the first term is given as $a_{1}$ .

⇒ $a_{1} = 612$

Now, the geometric sequence follows as 612, 661, ........

<u>The common ratio (r) :</u>

It is the ratio between two consecutive numbers in the sequence.

Therefore, to determine the common ratio, you just divide the number from the number preceding it in the sequence.

⇒ r = 661 divided by 612

⇒ r = 1.08

<u>To find the recursive rule :</u>

A geometric series is of the form a,ar,ar2,ar3,ar4,ar5........

Here, first term $a_{1} = a$ and other terms are obtained by multiplying by r.

Observe that each term is r times the previous term.
Hence to get nth term we multiply (n−1)th term by r .

The recursive rule is of the form $a_{n} = a^{n-1} \times r$

This is called recursive formula for geometric sequence.

We know that r = 1.08 and $a_{1}$ = 612.

To find the second term $a_{2}$ , use the recursive rule $a_{n} = a^{n-1} \times r$

⇒ $a_{2} = a^{2-1}\times r$

⇒ $a_{2} = a^{1}\times r$

⇒ $a_{2} = 612\times 1.08$

⇒ $a_{2} = 661$

3 0

3 years ago

two ferries start moving toward each other from opposite riverbanks, a and b. when they pass each other for the first time, the

Usimov [2.4K]

Let 'x' be the distance from THE far bank where 700 is the distance to the NEAR bank

boat one has travelled 700 (rate = 700/unit time) boat two has travelled x rate = x / unit time

boat one then travels x + 400 more and boat two travels 700 + (700+x -400) more when they meet

The time is the same rate x time = distance distance/rate = time equate the distances divided by the respective rates

(700 + x + 400)/700 = ( x + 700 + (700+x-400) )/x

1100x + x^2 = 1400x + 700000

x^2-300x -700000 = 0 quadratic formula yields x = 1000

One boat travels 700 the other 1000 whe they first meet.....width of river = 700+ 1000 = 1700 m

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3 years ago