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love history [14]
3 years ago
10

What is the equation of a line that passes trough (6,-1) and is parallel to the line that has a slope of -2/3?

Mathematics
1 answer:
ludmilkaskok [199]3 years ago
4 0

Answer:

y=-2/3x+3

Step-by-step explanation:

First, identify the slope you need for your equation. The keyword here is "parallel" so the slope you need is the same as the given slope (-2/3).

Next, use the ordered pair (6,-1); it's on the line that you need to find the equation for. Using slope-intercept form (y=mx+b), plug the -1 in for y, plug the 6 in for x, and plug in your slope of -2/3 for m. Solve for b, your y-intercept. You should get 3.

You have your slope and y-intercept now. Create your equation:

y=-2/3x+3.

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<u><em>Dimension of box:-</em></u>

Side of square base = 10 in

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Step-by-step explanation:

An open box with a square base is to have a volume of 500 cubic inches.

Let side of the base be x and height of the box is y

Volume of box = area of base × height

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Therefore, y=\dfrac{500}{x^2}

It is open box. The surface area of box, S .

S=x^2+4xy

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This would be rational function of surface area.

For maximum/minimum to differentiate S(x)

S'(x)=2x-\dfrac{2000}{x^2}

For critical point, S'(x)=0

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Put x = 10 into y=\dfrac{500}{x^2}

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Double derivative of S(x)

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