All categories

3 years ago

Graph the line with slope -1/2 passing through the point (-2, 4).

Mathematics

1 answer:

UkoKoshka [18]3 years ago

6 0

This image should help with that.

You might be interested in

BRAINLIEST AND EXTRA POINTS! ANY FAKE ANSWERS WILL BE REPORTED! 1. Write a completely simplified rational expression that repres

balandron [24]

Answer:

You did not give a amount for how much Salma has.

Step-by-step explanation:

8 0

2 years ago

What's the awnser to the one about Isabella

Irina18 [472]

I cant even see the picture clearly

6 0

2 years ago

What is the range of 17, 12, 28, 21, 14, 74, 32, 14, 25, 23

natita [175]

Answer:

it's 22 I hope you got it right if not then i'm sorry

8 0

2 years ago

Read 2 more answers

The camp is divided into2 groups. Thereare 14 kids in Camp A and 21 kids in Camp B. If you divided both camps into groups of equ

frez [133]

Answer: 7 students

Step-by-step explanation:

From the question, we are informed that there a camp is divided into2 groups and that there are 14 kids in Camp A and 21 kids in Camp B.

If the camps are divided into groups of equal size, there will be 7 students in a group. This will be gotten from :

Camp A = 14/2 = 7 students

Camp B = 21/3 = 7 students

8 0

3 years ago

MATH HELP!!! 100PTS!!!

Lostsunrise [7]

Answer:

$x =\dfrac{20 +\sqrt{454}}{18}, \quad \dfrac{20 -\sqrt{454}}{18}$

Step-by-step explanation:

Given functions:

$p(x)=2x-4$

$r(x)=\dfrac{6x-1}{9x+1}$

Solve for p(x) = r(x):

$\begin{aligned}p(x) & = r(x)\\\implies 2x-4 & = \dfrac{6x-1}{9x+1}\\(2x-4)(9x+1)&=6x-1\\18x^2+2x-36x-4&=6x-1\\18x^2-40x-3&=0\end{aligned}$

As the found quadratic equation cannot be factored, use the Quadratic Formula to solve for x:

Quadratic Formula

$x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when }\:ax^2+bx+c=0$

Therefore:

$a=18, \quad b=-40, \quad c=-3$

Substitute the values of a, b and c into the quadratic formula and solve for x:

$\begin{aligned}\implies x & =\dfrac{-(-40) \pm \sqrt{(-40)^2-4(18)(-3)} }{2(18)}\\\\& =\dfrac{40 \pm \sqrt{1816}}{36}\\\\& =\dfrac{40 \pm \sqrt{4 \cdot 454}}{36}\\\\& =\dfrac{40 \pm \sqrt{4}\sqrt{454}}{36}\\\\& =\dfrac{40 \pm2\sqrt{454}}{36}\\\\& =\dfrac{20 \pm\sqrt{454}}{18}\end{aligned}$

Therefore, the solutions are:

$x =\dfrac{20 +\sqrt{454}}{18}, \quad \dfrac{20 -\sqrt{454}}{18}$

Learn more about quadratic equations here:

brainly.com/question/27750885

brainly.com/question/27739892

6 0

1 year ago