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Digiron [165]
3 years ago
11

A group of botanists observe four types of plants for one week.

Mathematics
1 answer:
Arada [10]3 years ago
7 0
They are all linear.  Because they all increase steadily each day.
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Determine which point is the solution to the given system.
KatRina [158]

Answer:

D

Step-by-step explanation:

We equate both the y's and solve for x algebraically:

-\frac{4}{7}x+16=-\frac{2}{7}x+12\\16-12=-\frac{2}{7}x+\frac{4}{7}x\\4=\frac{2}{7}x\\x=\frac{4}{\frac{2}{7}}\\x=14

Now taking the value x= 14 and putting it in the 1st equation would give us y:

y=-\frac{4}{7}x+16\\y=-\frac{4}{7}(14)+16\\y=8

Hence the solution is (14,8), answer is D

7 0
4 years ago
Solve the system of equations by substitution.<br><br> y=5x-13<br> 5x+2y=19
Assoli18 [71]
<span>  x=<span><span><span><span>3‌</span>‌ and </span>‌</span>‌y</span></span>=<span>2   to check use the first equation y=5x-13  you plug in x which is 3 5 times 3 equals 15 15-13 equals 2 y=2</span>
8 0
4 years ago
F(x) = x(x - 5)2(x + 1)<br>questions to consider<br>Where are the zeros?​
ELEN [110]

Answer: I think the zeros are the X s in the equation.

Step-by-step explanation:

I hope I helped you!

7 0
3 years ago
A standard unit of measurement in astronomy is the astronomical unit, or au. it equals is about 150,000,000,000 m. in 2000, pion
Maurinko [17]

First we convert the m to km by dividing the number by 1000. 1000m = 1 km.

150,000,000,000 / 1000 = 150,000,000 km

Now we divide 150,000,000/11,000,000 = 13.6363636364 au.

8 0
3 years ago
How do you solve this problem?
enot [183]
Easy, it says "for ANY positive integer" so just test any positive integer

remember that n! means times all integers from 1 to that number n

lets try 1

(1+1)!/(1!)-1=
(2!)/(1!)-1=
2/1-1=
2-1=
1

if you don't believe me, try 2
(2+1)!/(2!)-2=
(3!)/(2!)-2=
(6)/(2)-2=
3-2=
1

te answer is 1, B


and number 9
easy, remember the exponential law
(x^m)(x^n)=x^(m+n)
jsut add the exponents
first gropu like bases
(r^2r^2/3)(t^1/2t^-3/2)
add bases
(r^2 and 2/3)(t^-1)=
(r^2∛(r^2))(1/t)=
\frac{r^{2} \sqrt[3]{r^{2}} }{t}
5 0
3 years ago
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