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ivanzaharov [21]
3 years ago
8

Write an expression that evaluates to true if the value of the int variable numberOfPrizes is divisible (with no remainder) by t

he int variable numberOfParticipants. Assume that numberOfParticipants is not zero.
Computers and Technology
1 answer:
Elodia [21]3 years ago
6 0

Answer:

import java.util.Scanner;

public class TestClock {

   public static void main(String[] args) {

   Scanner in = new Scanner(System.in);

       System.out.println("Enter number of prices");

       int numberOfPrizes = in.nextInt();

       System.out.println("Enter number of participants");

       int numberOfParticipants = in.nextInt();

        boolean isDivisible;

        if(numberOfPrizes%numberOfParticipants==0){

            isDivisible=true;

            System.out.println("True");

        }

        else {

            isDivisible=false;

            System.out.println("False");

        }

   }

}

Explanation:

Using Java Language;

  1. Prompt user to enter the number of prices and number of participants using the scanner class
  2. receive and save values in the variables numberOfPrizes and numberOfParticipants
  3. Create  a boolean variable (isDivisible)
  4. Using if statement and the modulo operator (%) which returns the remainder of division check if numberOfPrizes divieds evenly by numberOfParticipants.
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Write a program that allows the user to enter a start time and a future time. Include a function named compute Difference that t
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Step 1

Following is the c++ program:

Variables used:

startHours, startMins are used to store the starting time of time machine.

futureHours, futureMins are used to store the future time of time machine.

xAM variable is used to store meridiem of start and future time.

isSAM is boolean variable that is true if starting time is AM.

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Functions:

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computeDifference() takes as input six variables from the user and then apply the following logic to compute the difference between the start and future time:

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If Meridien of both start and future time are different, then apply the following formula to calculate difference:

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Step 2

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using namespace std;

//calculate the time difference(in minutes) between start time and future time.

int computeDifference(int startHours, int startMins, bool isSAM, int futureHours, int futureMins, bool isFAM) {

 int difference = 0; //to store difference

 startMins = startHours * 60 + startMins; //converting in minutes.

 futureMins = futureHours * 60 + futureMins; //converting in minutes.

 //applying formula for difference.

 if (isSAM == isFAM) {

   difference = futureMins - startMins;

 } else if (isSAM == true && isFAM == false) {

   difference = (12 * 60 - startMins) + futureMins;

 }

}

int main() {

 int startHours, startMins; //it will store start time

 int futureHours, futureMins; //it will store future time.

 string xAM; //it will store meridiem.

 bool isSAM; //it will be true if start time is AM.

 bool isFAM; //it will be true if future time is in AM.

 int difference = 0; //it will store difference.

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