Answer:
~CaptnCoderYankee
Don't forget to award brainlyest if I got it right!
Answer:
I'm pretty sure it's the first answer.
Explanation:
Let the size of a large server be L, and
the size of a small server be S.
We are given two scenarios,
2L+4S = 64.............(1)
and
L+3S = 40...............(2)
We solve the equations as follows
2(2)-(1)
2L-2L +6S-4S = 2*40-64
2S = 16
so S=8 ..................(3), size of small server
substitute (3) in (2)
L+3(8) =40
L = 40-24 = 16..............size of large server
