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3 years ago

the graph of a system of equations will intersect at exactly one point. a)always. b)sometimes. c)never

Mathematics

1 answer:

snow_tiger [21]3 years ago

4 0

(A) always .................

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Elden [556K]

Answer:

Heres how you do it

Step-by-step explanation:

10+2 =12 which means 72

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3 years ago

Please help, I don't know how to do this and need it done quickly, thanks for your help and time! have a good day :)

Olenka [21]

Sin50° = BC/3
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3 years ago

Write the expression as the sine, cosine, or tangent of an angle. sin 5x cos x - cos 5x sin x

mrs_skeptik [129]

Answer:

sin 5x cos x - cos 5x sin x = sin(4x)

Step-by-step explanation:

Given that the trigonometric expression,

sin 5x cos x - cos 5x sin x

Here we use the "sum and difference formulas"

Sum and Difference Formulas

sin(A+B)=sin A cos B + cos A sin B

sin(A-B)=sin A cos B - cos A sin B

cos(A+B)=cos A cos B - sin A sin B

cos(A-B)=cos A cos B + sin A sin B

So,

sin 5x cos x - cos 5x sin x = sin (5x - x)

sin 5x cos x - cos 5x sin x = sin(4x)

That's the final answer.

6 0

4 years ago

Use synthetic division to solve (x^3+1)/(x-1). What is the quotient?

Sav [38]

Answer:

x^2 +x +1

Step-by-step explanation:

See below for the tableau. The quotient is x^2 +x +1.

___

The remainder is 2.

7 0

4 years ago

If the endpoints of the diameter of a circle are (−8, −6) and (−4, −14), what is the standard form equation of the circle? A) (x

Andrei [34K]

Answer:

$\large\boxed{A.\ (x+6)^2+(y+10)^2=20}$

Step-by-step explanation:

The standard form of an equation of a circle:

$(x-h)^2+(y-k)^2=r^2$

(h, k) - center

r - radius

We have the endpoints of the diameter of a circle (-8, -6) and (-4, -14).

The midpoint of a diameter is a center of a circle.

The formula of a midpoint:

$\left(\dfrac{x_1+x_2}{2},\ \dfrac{y_1+y_2}{2}\right)$

Substitute:

$x=\dfrac{-8+(-4)}{2}=\dfrac{-12}{2}=-6\\\\y=\dfrac{-6+(-14)}{2}=\dfrac{-20}{2}=-10$

We have h = -6 and k = -10.

The radius is the distance between a center and the point on a circumference of a circle.

The formula of a distance between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Substitute (-6, -10) and (-8, -6):

$r=\sqrt{(-8-(-6))^2+(-6-(-10))^2}=\sqrt{(-2)^2+4^2}=\sqrt{4+16}=\sqrt{20}$

Finally we have

$(x-(-6))^2+(y-(-10))^2=(\sqrt{20})^2\\\\(x+6)^2+(y+10)^2=20$

5 0

4 years ago

Read 2 more answers

the graph of a system of equations will intersect at exactly one point. a)always. b)sometimes. c)never​

the graph of a system of equations will intersect at exactly one point. a)always. b)sometimes. c)never