3 years ago

Here are 15 cards, numbered 1 through 15. if you pick a card, what is the probability that you choose an odd number or a two?

Mathematics

1 answer:

kondor19780726 [428]3 years ago

5 0

9/15. There are 15 cards and 8 of them are odd and 1 is a 2.

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2 years ago

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larisa86 [58]

Answer: option a its 2

Step-by-step explanation:

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12/15,3/4,3/12 as a decimal/ how to get the answer

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3 years ago

How can csc^2-cot^2 = 1?

Softa [21]

ANSWER

By simplifying the left hand side using the Pythagorean Identity.

EXPLANATION

The given identity is

$\csc^{2} (x) - \cot^{2} (x) = 1$

Take the left hand side and simplify to get the right hand side.

$\csc^{2} (x) - \cot^{2} (x) = \frac{1}{\sin^{2} (x)} - \frac{ \cos^{2} (x)}{\sin^{2} (x)}$

Collect LCM for the denominators.

$\csc^{2} (x) - \cot^{2} (x) = \frac{1 - \cos^{2} (x)}{\sin^{2} (x)}$

Recall the Pythagorean Identity.

$\cos^{2} (x) + \sin^{2} (x) = 1$

This implies that:

$1 - \cos^{2} (x) = \sin^{2} (x)$

We substitute this to get,

$\csc^{2} (x) - \cot^{2} (x) = \frac{\sin^{2} (x)}{\sin^{2} (x)}$

$\csc^{2} (x) - \cot^{2} (x) = 1$

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2 years ago

Pls help extra points and mark brainlist

igor_vitrenko [27]

Answer:

2over/a -b-c

Step-by-step explanation:

remove the parentheses

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