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andreyandreev [35.5K]
3 years ago
6

This is confusing. can someone please help

Mathematics
2 answers:
kolezko [41]3 years ago
8 0
For finding the measure of C you should know a line is 180° so 124°+C = 180 
now you can say: 
C = 180°- 124° = 56 ° 
so the answer is 56° :)))
i hope this is helpful 
have a nice day 
andrey2020 [161]3 years ago
4 0
The answer is 56. 180-124=56.
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Javier teaches yoga classes at his community center. In a 60-minute class last night, he taught 30 poses. Today, he has a 30-min
Hatshy [7]

Answer:

Step-by-step explanation

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2 years ago
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Given: ΔPSQ, PS = SQ
horrorfan [7]
<h2>Answer:</h2>

To solve this problem we will use Heron's formula:

A=\sqrt{s(s-a)(s-b)(s-c)}

Where a, \ b \ and \ c are the side lengths of the triangle and s is the semiperimeter (half the perimeter of the triangle). We know that:

Perimeter \ P=\triangle PSQ=PS+PQ+SQ: \\ \\ \triangle PSQ=P=50 \\ \\ Semiperimeter \ s: \\ \\ s=\frac{P}{2}=25

Also:

(I) \ PS=SQ \\ \\ (II) \ SQ-PQ = 1 \\ \\ (III) \ PS+PQ+SQ=50 \\ \\ \\ (I) \ into \ (III): \\ \\ SQ+PQ+SQ=50 \\ \\ \therefore (IV) \ 2SQ+PQ=50 \\ \\ From \ (II): \\ \\ PQ=SQ-1 \\ \\ (II) \ into \ (IV): \\ \\ 2SQ+(SQ-1)=50 \\ 3SQ-1=50 \\ 3SQ=51 \\ \\ \boxed{SQ=17} \\ \\ \boxed{PS=17} \\ \\ PQ=SQ-1=17-1 \therefore \boxed{PQ=16}

Finally:

A=\sqrt{s(s-a)(s-b)(s-c)} \\ \\ A=\sqrt{s(s-PS)(s-SQ)(s-PQ)} \\ \\ A=\sqrt{s(s-17)(s-17)(s-16)} \\ \\ A=\sqrt{25(25-17)(25-17)(25-16)} \\ \\ \boxed{A=120}

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3 years ago
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Answer:

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