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yuradex [85]
3 years ago
15

Question 1

Mathematics
1 answer:
xxTIMURxx [149]3 years ago
3 0

Answer:

The teacher randomly divides the class into two groups. One of the groups receives computer-based instruction and the other group receives traditional instruction without computers. After instruction, each student takes a test and the teacher wants to compare the test scores of the two groups.

Step-by-step explanation:

A two sample t-test is used to compared the means of two samples who were exposed to different scenarios and therefore, it helps us to see the difference between these two samples.

In this problem, the teacher is experimenting with a new computer-based instruction. To be able to use the two-sample t-test she would have to have two randomly assigned samples and expose each of these two samples to different scenarios (one would receive a traditional instruction and the other one would receive a computer instruction), and finally she would need to compare the scores in both samples.

Therefore, the correct answer would be b) The teacher randomly divides the class into two groups. One of the groups receives computer-based instruction and the other group receives traditional instruction without computers. After instruction, each student takes a test and the teacher wants to compare the test scores of the two groups.

<u>*Option A is incorrect</u> because the students are only exposed to the lesson using a computer program and therefore they aren't exposed to different scenarios.

<u>*Option C is incorrect</u> because although in this case the teacher uses both traditional and computer methods, there are not two different samples and she only gets the opinion of the students which is not an exact method of getting information on the effectiveness of the computer based method.

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14. At the museum, the O'Rourke family
vekshin1

Answer:

\large \boxed{A = \$5.50; C = \$3.50}

Step-by-step explanation:

Let A = cost of adult ticket

And C =  cost of child's ticket. Then,  

\begin{array}{rcll}(1) \qquad 3A + 2C & = & 23.50&\\(2) \qquad 2A + 4C & = &25.00&\\(3) \qquad 6A + 4C & = &47.00&\text{Doubled (1)}\\4A & = & 22.00&\text{Subtracted (2) from (3)}\\(4) \qquad \qquad \quad A & = & \mathbf{5.50}&\text{Divided each side by 4}\\\end{array}\\

\begin{array}{rcll}11.00 + 4C & = &25.00& \text{Substituted(4) into (2)}\\4C &=& 14.00&\text{Subtracted 11.00 from each side}\\C &=& \mathbf{3.50}&\text{Divided each side by 4}\\\end{array}\\\text{The ticket costs are $\large \boxed{\mathbf{A = \$5.50; C = \$3.50}}$}

Check:

\begin{array}{cccl}3(5.50) + 2(3.50) = 23.50 & \qquad & 2(5.50) + 4(3.50) = 25.00\\16.50 + 7.00 = 23.50 & \qquad & 11.00 + 14.00 = 25.00\\23.50 = 23.50 & \qquad & 25.00 = 25.00\\\end{array}

OK.

7 0
3 years ago
Highland missed 16 out of 78 points on his last test. What letter grade did he earn?
Papessa [141]

The letter grade he got was around a C or a low B.


8 0
3 years ago
Read 2 more answers
Bir sınıfta 15kişi ingilizce,6kisi ingilizce fransizca ,10kisi ise fransizca konusmaktadir bunw gore sinifta öğrenci sayısı kact
nataly862011 [7]

Answer:

Cavap:31

Step-by-step explanation:

  • 15+10+6=31
  • YARDIMCI OLDUYSAM TŞK EDERIM
  • EN İYİ CEVAP SEÇERMİSİN????

6 0
2 years ago
Gabriel is making a mixture of compost and soil to use for a special plan he wants his final mix to be two part compost to 10 pa
kkurt [141]
Ten is mistakenly written by Tim in question.
Gabriel is making a mixture of compost and soil. In which he wants to mix 2 part compost to 10 parts potting soil. And he wants to end up with ten kilogram
It means compost is 2 pars out of 12 and potting soil is 10 parts out of 12
so, (2 / 12) x 10 kilogram of compost is used
= 1.66667 kilogram of compost Gabriel should use.

8 0
3 years ago
Please help<br><br>numbers 42, 43, 44
Aleks [24]
<h3>Answer:</h3>

42.  29°

43.  3x³ +2x² -3x +10

44.  20a² +68a

<h3>Step-by-step explanation:</h3>

42.  The right-angle corner tells you the two marked angles are complementary — they sum to 90°.

  (-3x +20)° + (-2x +55)° = 90°

  -5x +75 = 90 . . . . . . . . . . collect terms, divide by °

  -5x = 15 . . . . . . . . . . . . . . . subtract 75

  x = -3 . . . . . divide by the coefficient of x

The angle of interest is (-3x+20)°. Filling in the found value for x, we have ...

  (-3·(-3) +20)° = 29° = m∠BDC

___

43.  The distributive property is useful for multiplying polynomials.

  (x +2)(3x² -4x +5) = x(3x² -4x +5) +2(3x² -4x +5)

  = 3x³ -4x² +5x +6x² -8x +10 . . . . . eliminate parentheses

  = 3x³ +2x² -3x +10

___

44.  Area is the product of length and width, so this becomes a problem in multiplying polynomials.

  area = (5a +17)(4a) = 20a² +68a . . . . area in square feet

3 0
2 years ago
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