Please help with 19 and 20 and explain

Consider the two triangles. Triangles A B C and H G I are shown. Angles A C B and H I G are right angles. The length of side A C

zheka24 [161]

Answer:

Both are similar by SAS similarity.

This SAS similarity is equivalent to the congruence.

Step-by-step explanation:

Step 1:

To prove that ACB and HIG as similar triangles.

We have to look upon the corresponding sides.

SAS= Side angle sides , there the angle must be in between two sides.

$\angle$ ACB = $\angle$ HIG

Lets work on the corresponding sides.

IG/AC = IH/AC

$\frac{9}{15}$ = $\frac{12}{20}$

Reducing each to lowest form, we divide numerator and denominator by 3 for the 1st fraction and by 4 for the 2nd fraction.

We have

$\frac{3}{5}$ = $\frac{3}{5}$

Both sides are equal.

So its proved that both are similar with SAS similarity theorem.

8 0

3 years ago

Read 2 more answers

This figure is made up of a rectangle and parallelogram.

patriot [66]

calculate length of the sides of the rectangle and multiply then do the same with the parallelogram

Total area is 51 square units

7 0

4 years ago

when the wimen sells 90 oranges Rs160 with dicount of 20%,how many oranges she sell by Rs112 with profit of 20%

Fynjy0 [20]

She sold 42 oranges with profit 20%

Step-by-step explanation:

The woman sells 90 oranges by RS.160

This price with discount of 20%

We need to find how many oranges she sell by Rs.112 with profit of 20%

Selling price = cost price - discount ⇒ discount case
Selling price = cost price + profit ⇒ profit case

Assume that cost price of an orange is x

∵ She sells 90 oranges with Rs.160

- Find the selling price of 1 orange by dividing 160 by 90

∴ The selling price of an orange = $\frac{160}{90}=\frac{16}{9}$

∵ She sold them with discount 20%

∵ The cost price of an orange is x

- Find the 20% of x

∵ Discount = 20% × x = $\frac{20}{100}$ × x = 0.2x

- To find the selling price subtract 0.2x from x

∴ The selling price = x - 0.2x

∴ The selling price of an orange = 0.8x

- Equate 0.8x by $\frac{16}{9}$ to find x

∵ 0.8x = $\frac{16}{9}$

- Divide both sides by 0.8

∴ x = $\frac{20}{9}$

Assume that the number of oranges is y

∵ She sell y oranges for Rs.112 with profit 20%

∵ The cost price of an orange is $\frac{20}{9}$

- Find 20% of $\frac{20}{9}$

∵ Profit = 20% × $\frac{20}{9}$ = $\frac{20}{100}.\frac{20}{9}=\frac{4}{9}$

- Add $\frac{4}{9}$ to cost price to find the selling price

∴ The selling price of an orange = $\frac{20}{9}$ + $\frac{4}{9}$

∴ The selling price of an orange = $\frac{24}{9}$

- To find y divide 112 by selling price of an orange

∵ y = 112 ÷ $\frac{24}{9}$

∴ y = 42

She sold 42 oranges with profit 20%

Learn more:

You can learn more about percentage in brainly.com/question/12284722

#LearnwithBrainly

4 0

3 years ago

Someone help pleasee

dezoksy [38]

It’s -3/2 :) Hope this helps!

8 0

4 years ago

The area of a regular octagon is 35 cm 2 what is the area of a regular octagon with sides three times as large

Maurinko [17]

The area of a polygon = n*side^2 / (4 * tan(180/n))
where "n" is the number of sides

Let's calculate area for side = 2
area = 8*2^2 / (4 * tan(180/8))
area = 32 / (4 * tan(22.5))
area = 32 / 4*0.41421
 area = 19.3138746047 

Now, let's calculate area for side = 6
area = 8*6^2 / (4 * tan(180/8))
area = 288 / 1.65684 
area = 173.824871442 

 173.824871442 / 19.3138746047 = 9

So, the area would be 9 times larger.

ALSO, looking at the formula
n*side^2 / (4 * tan(180/n))
we can see that the side length appears just once in the formula and we are to square it in the calculation. So, if we increase the side length is increased by 3, then the area increases by 3^2 or 9.

5 0

3 years ago