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3 years ago

How many energy levels do aluminum, argon and sodium have?plz help

Chemistry

1 answer:

Sloan [31]3 years ago

6 0

Answer:

aluminum - 3,argon - 3,sodium - 3

Explanation:

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The rate law for the decomposition of phosphine () is It takes 135. s for 1.00 M to decrease to 0.250 M. How much time is requir

vova2212 [387]

Answer:

189.71 secs

Explanation:

We know that decomposition is a first order reaction;

So;

ln[A] = ln[A]o - kt

But;

[A]o = 1.00 M

[A] = 0.250 M

t =135 s

Hence;

ln[A] - ln[A]o = kt

k = ln[A] - ln[A]o/t

k = ln(1) - ln(0.250)/135

k =0 - (-1.386)/135

k = 1.386/135

k= 0.01

So time taken now will be;

ln[A] - ln[A]o = kt

t = ln[A] - ln[A]o/k

t = ln (3) - ln(0.450)/0.01

t = 1.0986 - (-0.7985)/0.01

t = 1.0986 + 0.7985/0.01

t = 189.71 secs

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3 years ago

Carbon and sodium chloride are both extended structures. What are the main differences between these two kinds of extended struc

Julli [10]

Carbon is what you breathe out and chloride is like somewhere in your immune system

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3 years ago

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A meteorologist filled a weather balloon with 3.00L of the inert noble gas helium. The balloon's pressure was 765 torr. The ball

yanalaym [24]

Answer:

4.33 L

Explanation:

Step 1: Given data

Initial volume of the balloon (V₁): 3.00 L

Initial pressure of the balloon (P₁): 765 torr

Final volume of the balloon (V₂): ?

Final pressure of the balloon (P₂): 530 torr

Step 2: Calculate the final volume of the balloon

If we consider Helium to behave as an ideal gas, we can calculate the final volume of the balloon using Boyle's law.

$P_1 \times V_1 = P_2 \times V_2\\V_2 = \frac{P_1 \times V_1}{P_2} = \frac{765torr \times 3.00L}{530torr} = 4.33 L$

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3 years ago

What is the difference between the substances represented by the symbols Co and CO

Finger [1]

Answer:

Be careful about when to use capital letters. For example, CO means a molecule of carbon monoxide but Co is the symbol for cobalt

Explanation:

6 0

3 years ago

Suppose of sodium chloride is dissolved in of a aqueous solution of ammonium sulfate. Calculate the final molarity of sodium cat

mariarad [96]

Answer:

0.103 M.

Explanation:

The balanced equation of reaction is given below;

2NaCl + (NH4)2SO4 -----------------> Na2SO4 + 2NH4Cl

The parameters given from the question are; mass of Sodium chloride, NaCl = 0.197 g, the volume of ammonium sulphate is 100 mL = 0.1 litres, concentration of ammonium sulfate = 54.0mM = 0.054 mol/L.

Step one: Calculate the number of moles of NaCl by using the formula below;

Number of moles,n= mass/ mass number.

Number of moles,n = 0.917/ 58.5.

Number of moles, n= 0.0157 g/mol.

Step two: find the number of moles of ammonium sulfate.

Hence, the number of moles of ammonium sulfate, n = concentration (mol/L) of ammonium sulfate × volume.

Therefore, the number of moles of ammonium sulfate, n = 0.054 × 0.1.

the number of moles of ammonium sulfate, n = 0.0054 mol.

Step three: Calculate the excess moles of NaCl.

That is; 0.0157 - 0.0054 = 0.0103 mol.

Step four: Calculate the final molarity of sodium cation in the solution.

[Na^+] = number of moles/ total volume.

[Na^+] = 0.0103 mol/ 0.1.

0.0103 mol= 0.103 M.

5 0

3 years ago